我不确定为什么以下控制台应用程序不会产生last_insert_id()的预期行为。我已经读过last_insert_id()返回特定连接的最后一个auto_incremented值,但是在这段代码中,两个连接都返回相同的结果。有人可以解释我出错的地方吗?
static void Main(string[] args)
{
string ConnectionString = "server=XXXX;database=XXXX;username=XXXX;password=XXXX;pooling=true;max pool size=100;min pool size=0";
MySqlConnection conn1 = new MySqlConnection(ConnectionString);
MySqlConnection conn2 = new MySqlConnection(ConnectionString);
MySqlCommand command1 = new MySqlCommand();
MySqlCommand command2 = new MySqlCommand();
command1.Connection = conn1;
command2.Connection = conn1;
StringBuilder createTableCommandText = new StringBuilder();
createTableCommandText.Append("Create Table TestTable (");
createTableCommandText.Append("Id INT NOT NULL AUTO_INCREMENT, ");
createTableCommandText.Append("str VARCHAR(20) NOT NULL, ");
createTableCommandText.Append("PRIMARY KEY (Id));");
StringBuilder insertCommandText = new StringBuilder();
insertCommandText.Append("INSERT INTO TestTable (str) VALUES ('what is the dilleo?');");
StringBuilder getLastInsertId = new StringBuilder();
getLastInsertId.Append("SELECT LAST_INSERT_ID();");
conn1.Open();
conn2.Open();
command1.CommandText = createTableCommandText.ToString();
command1.ExecuteNonQuery();
command1.CommandText = insertCommandText.ToString();
command2.CommandText = insertCommandText.ToString();
command1.ExecuteNonQuery();
command2.ExecuteNonQuery();
command1.CommandText = getLastInsertId.ToString();
Console.WriteLine("Command 1: {0}", command1.ExecuteScalar().ToString());
command2.CommandText = getLastInsertId.ToString();
Console.WriteLine("Command 2: {0}", command2.ExecuteScalar().ToString());
conn1.Close();
conn2.Close();
Console.ReadLine();
}
我知道这没有发生,因为在顶部的连接字符串中存在池,因为我尝试在没有字符串的那一部分的情况下运行程序,我仍然得到相同的结果(即命令1和命令2显示了last_insert_id()的相同值。欢迎任何想法!
非常感谢,
安德鲁
答案 0 :(得分:2)
看这里:
command1.Connection = conn1;
command2.Connection = conn1;
您对两个命令使用相同的连接。