是否存在实现某种展平迭代器的现有迭代器实现（可能在boost中）？
例如：
unordered_set<vector<int> > s;
s.insert(vector<int>());
s.insert({1,2,3,4,5});
s.insert({6,7,8});
s.insert({9,10,11,12});
flattening_iterator<unordered_set<vector<int> >::iterator> it( ... ), end( ... );
for(; it != end; ++it)
{
cout << *it << endl;
}
//would print the numbers 1 through 12
答案 0 :(得分：41)
我不知道主要库中的任何实现，但它看起来像一个有趣的问题所以我写了一个基本的实现。我只用我在这里提供的测试用例进行了测试，因此我不建议在没有进一步测试的情况下使用它。
问题比它看起来有点棘手，因为一些“内部”容器可能是空的，你必须跳过它们。这意味着将flattening_iterator推进一个位置实际上可以将迭代器推进到“外部”容器中多个位置。因此，flattening_iterator需要知道外部范围的结束位置，以便知道何时需要停止。
此实现是一个前向迭代器。双向迭代器还需要跟踪外部范围的开始。 flatten函数模板用于使构造flattening_iterator更容易。
#include <iterator>
// A forward iterator that "flattens" a container of containers. For example,
// a vector<vector<int>> containing { { 1, 2, 3 }, { 4, 5, 6 } } is iterated as
// a single range, { 1, 2, 3, 4, 5, 6 }.
template <typename OuterIterator>
class flattening_iterator
{
public:
typedef OuterIterator outer_iterator;
typedef typename OuterIterator::value_type::iterator inner_iterator;
typedef std::forward_iterator_tag iterator_category;
typedef typename inner_iterator::value_type value_type;
typedef typename inner_iterator::difference_type difference_type;
typedef typename inner_iterator::pointer pointer;
typedef typename inner_iterator::reference reference;
flattening_iterator() { }
flattening_iterator(outer_iterator it) : outer_it_(it), outer_end_(it) { }
flattening_iterator(outer_iterator it, outer_iterator end)
: outer_it_(it),
outer_end_(end)
{
if (outer_it_ == outer_end_) { return; }
inner_it_ = outer_it_->begin();
advance_past_empty_inner_containers();
}
reference operator*() const { return *inner_it_; }
pointer operator->() const { return &*inner_it_; }
flattening_iterator& operator++()
{
++inner_it_;
if (inner_it_ == outer_it_->end())
advance_past_empty_inner_containers();
return *this;
}
flattening_iterator operator++(int)
{
flattening_iterator it(*this);
++*this;
return it;
}
friend bool operator==(const flattening_iterator& a,
const flattening_iterator& b)
{
if (a.outer_it_ != b.outer_it_)
return false;
if (a.outer_it_ != a.outer_end_ &&
b.outer_it_ != b.outer_end_ &&
a.inner_it_ != b.inner_it_)
return false;
return true;
}
friend bool operator!=(const flattening_iterator& a,
const flattening_iterator& b)
{
return !(a == b);
}
private:
void advance_past_empty_inner_containers()
{
while (outer_it_ != outer_end_ && inner_it_ == outer_it_->end())
{
++outer_it_;
if (outer_it_ != outer_end_)
inner_it_ = outer_it_->begin();
}
}
outer_iterator outer_it_;
outer_iterator outer_end_;
inner_iterator inner_it_;
};
template <typename Iterator>
flattening_iterator<Iterator> flatten(Iterator it)
{
return flattening_iterator<Iterator>(it, it);
}
template <typename Iterator>
flattening_iterator<Iterator> flatten(Iterator first, Iterator last)
{
return flattening_iterator<Iterator>(first, last);
}
以下是最小测试存根：
#include <algorithm>
#include <iostream>
#include <set>
#include <vector>
int main()
{
// Generate some test data: it looks like this:
// { { 0, 1, 2, 3 }, { 4, 5, 6, 7 }, { 8, 9, 10, 11 } }
std::vector<std::vector<int>> v(3);
int i(0);
for (auto it(v.begin()); it != v.end(); ++it)
{
it->push_back(i++); it->push_back(i++);
it->push_back(i++); it->push_back(i++);
}
// Flatten the data and print all the elements:
for (auto it(flatten(v.begin(), v.end())); it != v.end(); ++it)
{
std::cout << *it << ", ";
}
std::cout << "\n";
// Or, since the standard library algorithms are awesome:
std::copy(flatten(v.begin(), v.end()), flatten(v.end()),
std::ostream_iterator<int>(std::cout, ", "));
}
就像我刚开始说的那样，我没有彻底测试过。如果您发现任何错误，请告诉我，我们很乐意纠正错误。
答案 1 :(得分：6)
我决定对扁平迭代器概念进行“改进”，但正如詹姆斯所指出的那样，你使用Ranges（除了最里面的容器），所以我只是使用了范围贯穿并因此获得了一个扁平范围，具有任意深度。
首先我使用了建筑砖：
template <typename C>
struct iterator { using type = typename C::iterator; };
template <typename C>
struct iterator<C const> { using type = typename C::const_iterator; };
然后定义了一个（非常小的）ForwardRange概念：
template <typename C>
class ForwardRange {
using Iter = typename iterator<C>::type;
public:
using pointer = typename std::iterator_traits<Iter>::pointer;
using reference = typename std::iterator_traits<Iter>::reference;
using value_type = typename std::iterator_traits<Iter>::value_type;
ForwardRange(): _begin(), _end() {}
explicit ForwardRange(C& c): _begin(begin(c)), _end(end(c)) {}
// Observers
explicit operator bool() const { return _begin != _end; }
reference operator*() const { assert(*this); return *_begin; }
pointer operator->() const { assert(*this); return &*_begin; }
// Modifiers
ForwardRange& operator++() { assert(*this); ++_begin; return *this; }
ForwardRange operator++(int) { ForwardRange tmp(*this); ++*this; return tmp; }
private:
Iter _begin;
Iter _end;
}; // class ForwardRange
这是我们在这里的建筑砖，但事实上我们可以只做其余的事情：
template <typename C, size_t N>
class FlattenedForwardRange {
using Iter = typename iterator<C>::type;
using Inner = FlattenedForwardRange<typename std::iterator_traits<Iter>::value_type, N-1>;
public:
using pointer = typename Inner::pointer;
using reference = typename Inner::reference;
using value_type = typename Inner::value_type;
FlattenedForwardRange(): _outer(), _inner() {}
explicit FlattenedForwardRange(C& outer): _outer(outer), _inner() {
if (not _outer) { return; }
_inner = Inner{*_outer};
this->advance();
}
// Observers
explicit operator bool() const { return static_cast<bool>(_outer); }
reference operator*() const { assert(*this); return *_inner; }
pointer operator->() const { assert(*this); return _inner.operator->(); }
// Modifiers
FlattenedForwardRange& operator++() { ++_inner; this->advance(); return *this; }
FlattenedForwardRange operator++(int) { FlattenedForwardRange tmp(*this); ++*this; return tmp; }
private:
void advance() {
if (_inner) { return; }
for (++_outer; _outer; ++_outer) {
_inner = Inner{*_outer};
if (_inner) { return; }
}
_inner = Inner{};
}
ForwardRange<C> _outer;
Inner _inner;
}; // class FlattenedForwardRange
template <typename C>
class FlattenedForwardRange<C, 0> {
using Iter = typename iterator<C>::type;
public:
using pointer = typename std::iterator_traits<Iter>::pointer;
using reference = typename std::iterator_traits<Iter>::reference;
using value_type = typename std::iterator_traits<Iter>::value_type;
FlattenedForwardRange(): _range() {}
explicit FlattenedForwardRange(C& c): _range(c) {}
// Observers
explicit operator bool() const { return static_cast<bool>(_range); }
reference operator*() const { return *_range; }
pointer operator->() const { return _range.operator->(); }
// Modifiers
FlattenedForwardRange& operator++() { ++_range; return *this; }
FlattenedForwardRange operator++(int) { FlattenedForwardRange tmp(*this); ++*this; return tmp; }
private:
ForwardRange<C> _range;
}; // class FlattenedForwardRange
显然，it works
答案 2 :(得分：2)
我到达的地方有点晚了，但我刚刚发表了a library (multidim)来解决这个问题。用法很简单：使用你的例子，
#include "multidim.hpp"
// ... create "s" as in your example ...
auto view = multidim::makeFlatView(s);
// view offers now a flattened view on s
// You can now use iterators...
for (auto it = begin(view); it != end(view); ++it) cout << *it << endl;
// or a simple range-for loop
for (auto value : view) cout << value;
该库只是标题，没有依赖项。但需要C ++ 11。
答案 3 :(得分：1)
你可以在boost中使用迭代器外观制作一个。
我编写了可以用作模板的迭代器产品： http://code.google.com/p/asadchev/source/browse/trunk/work/cxx/iterator/product.hpp
答案 4 :(得分：0)
除了Matthieu的答案外，您还可以自动计算可迭代/容器的尺寸。但是首先，当某些东西是可迭代的/容器时，我们必须设置一条规则：
template<class T, class R = void>
struct AliasWrapper {
using Type = R;
};
template<class T, class Enable = void>
struct HasValueType : std::false_type {};
template<class T>
struct HasValueType<T, typename AliasWrapper<typename T::value_type>::Type> : std::true_type {};
template<class T, class Enable = void>
struct HasConstIterator : std::false_type {};
template<class T>
struct HasConstIterator<T, typename AliasWrapper<typename T::const_iterator>::Type> : std::true_type {};
template<class T, class Enable = void>
struct HasIterator : std::false_type {};
template<class T>
struct HasIterator<T, typename AliasWrapper<typename T::iterator>::Type> : std::true_type {};
template<class T>
struct IsIterable {
static constexpr bool value = HasValueType<T>::value && HasConstIterator<T>::value && HasIterator<T>::value;
};
我们可以对尺寸进行如下计算：
template<class T, bool IsCont>
struct CountDimsHelper;
template<class T>
struct CountDimsHelper<T, true> {
using Inner = typename std::decay_t<T>::value_type;
static constexpr int value = 1 + CountDimsHelper<Inner, IsIterable<Inner>::value>::value;
};
template<class T>
struct CountDimsHelper<T, false> {
static constexpr int value = 0;
};
template<class T>
struct CountDims {
using Decayed = std::decay_t<T>;
static constexpr int value = CountDimsHelper<Decayed, IsIterable<Decayed>::value>::value;
};
然后我们可以创建一个包含begin()和end()函数的视图包装器。
template<class Iterable, int Dims>
class Flatten {
public:
using iterator = FlattenIterator<Iterable, Dims>;
private:
iterator _begin{};
iterator _end{};
public:
Flatten() = default;
template<class I>
explicit Flatten(I&& iterable) :
_begin(iterable),
_end(iterable)
{}
iterator begin() const {
return _begin;
}
iterator end() const {
return _end;
}
};
为了简化对象Flatten的创建，我们定义了一个辅助函数：
template<class Iterable>
Flatten<std::decay_t<Iterable>, CountDims<Iterable>::value - 1> flatten(Iterable&& iterable) {
return Flatten<std::decay_t<Iterable>, CountDims<Iterable>::value - 1>(iterable);
}
用法：
std::vector<std::vector<int>> vecs = {{1,2,3}, {}, {4,5,6}};
for (int i : flatten(vecs)) {
// do something with i
}