Question

我试图在python中编写一个程序，使用几种不同的操作来计算（可能非常低效，但我离题）。但是，运行它时出现了一个我无法弄清楚的错误。我认为它需要定义变量的类型。该计划：

import math
print('Select a number.')
y = input()
print('Select another number.')
x = input()
print('Select what operation you wish to perform. (e for exponentiation, d for division, m for multiplication, a for addition, s for subtraction, mo for modulo, l for log (the base is the first number you entered), r for root)')
z = input()
if z == 'e' or z == 'E':
    print('The answer is ' + y**x)
elif z == 'd' or z == 'D':
    print('The answer is ' + y/z)
elif z == 'm' or z == 'M':
    print('The answer is ' + y*x)
elif z == 'a' or z == 'A':
    print('The answer is ' + y+x)
elif z == 's' or z == 'S':
    print('The answer is ' + y-x)
elif z == 'mo' or z == 'Mo':
    print('The answer is ' + y%x)
elif z == 'l' or z == 'L':
    print('The answer is ' + math.log(x,y))
elif z == 'r' or z == 'R':
    print('The answer is ' + y**(1/x))

shell中出现的错误：

Traceback (most recent call last):
  File "C:/Users/UserNameOmitted/Downloads/Desktop/Python/Calculator.py", line 7, in <module>
    z = input()
  File "<string>", line 1, in <module>
NameError: name 'd' is not defined

Answer 1

你必须做

z = raw_input()

同样输入在int中以python2.x的形式返回。因此，请使用raw_input作为str，然后将所有地方print('The answer is ' + y**x)改为print('The answer is ' + str(y**x))

Answer 2

这里有几个问题：

z应输入raw_input，而不是input。
在除法案例中，您要划分y/z而不是y/x。

Answer 3

您的代码有错误

使用raw_input（）获取字符串输入而不是input（）
使用int（raw_input（））来获取整数输入，这不是错误，但这是一种很好的做法。
你试图用字符串划分int。
您尝试连接字符串和整数。

您的代码应该是这样的。

import math
print('Select a number.')
y = int(raw_input())
print('Select another number.')
x = int(raw_input())
print('Select what operation you wish to perform. (e for exponentiation, d for division, m for multiplication, a for addition, s for subtraction, mo for modulo, l for log (the base is the first number you entered), r for root)')
z = raw_input()
if z == 'e' or z == 'E':
    print('The answer is %d'  %(y**x))
elif z == 'd' or z == 'D':
    print('The answer is %d'  %(y/x))
elif z == 'm' or z == 'M':
    print('The answer is %d'  %(y*x))
elif z == 'a' or z == 'A':
    print('The answer is %d'  %(y+x))
elif z == 's' or z == 'S':
    print('The answer is %d'  %(y-x))
elif z == 'mo' or z == 'Mo':
    print('The answer is %d'  %(y%x))
elif z == 'l' or z == 'L':
    print('The answer is %d'  %(math.log(x,y)))
elif z == 'r' or z == 'R':
    print('The answer is %d'  %(y**(1/x)))

我做的python计算器出错

3 个答案: