将搜索结果添加到Python中的表中

Question

我使用Python进行了搜索，得到了下面的结果，但是在将它保存到SQLite中的表时遇到了麻烦。具有3列（类别，名称，ID）的表

代码：

data = [{u'category': u'Local Business',
       u'category_list': [{u'id': u'145887745471348', u'name': u'Train Station'}],
       u'id': u'129926257075048',
       u'name': u'Southampton the Fit Student Central!'},
      {u'category': u'Local Business',
       u'category_list': [{u'id': u'2500', u'name': u'Local Business'}],
       u'id': u'151910741511395',
       u'name': u'Student Hell Train'},
      {u'category': u'Local Business',
       u'category_list': [{u'id': u'192119584190796', u'name': u'Event'}],
       u'id': u'159561157587886',
       u'name': u'Student Ambassador Training'}]


    stmt = "insert into Student_Mentors (category, name, id) values ({category}, {name}, {id})".format(**data)
    con.executemany(stmt, data)
    con.commit()

我收到以下错误...

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-174-58d2f1a67f61> in <module>()
     13 
     14 
---> 15 stmt = "insert into Student_Mentors (category, name, id) values ({category}, {name}, {id})".format(**data)
     16 con.executemany(stmt, data)
     17 con.commit()

TypeError: format() argument after ** must be a mapping, not list

不确定如何使其成为映射

Answer 1

sqlite3模块的paramstyle为qmark，意味着参数的占位符应为​​? s。

你需要使用如下：

stmt = "INSERT INTO Student_Mentors (category, name, id) VALUES (?, ?, ?)"
rows = [[row['category'], row['name'], row['id']] for row in data]
con.executemany(stmt, rows)
con.commit()