在我的活动中,我有一个ImageView。我想,当用户点击它时,会打开一个对话框(如意图对话框),显示可以打开图像的应用列表,而不是用户可以选择应用并使用该应用显示图像。
我的活动代码:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
ImageView iv = (ImageView) findViewById(R.id.imageid);
iv.setImageResource(R.drawable.dish);
iv.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
//here is where I want a dialog that I mentioned show
}
});
}// end onCreate()
答案 0 :(得分:2)
您无法将位图传递给意图。
从我看到你想要从你的资源中分享一个drawable。首先,您必须将drawable转换为位图。然后你必须将位图作为文件保存到外部存储器,然后使用Uri.fromFile(新文件(pathToTheSavedPicture))获取该文件的uri,并将该uri传递给这样的意图。
shareDrawable(this, R.drawable.dish, "myfilename");
public void shareDrawable(Context context,int resourceId,String fileName) {
try {
//convert drawable resource to bitmap
Bitmap bitmap = BitmapFactory.decodeResource(context.getResources(), resourceId);
//save bitmap to app cache folder
File outputFile = new File(context.getCacheDir(), fileName + ".png");
FileOutputStream outPutStream = new FileOutputStream(outputFile);
bitmap.compress(CompressFormat.PNG, 100, outPutStream);
outPutStream.flush();
outPutStream.close();
outputFile.setReadable(true, false);
//share file
Intent shareIntent = new Intent(android.content.Intent.ACTION_SEND);
shareIntent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(outputFile));
shareIntent.setType("image/png");
context.startActivity(shareIntent);
}
catch (Exception e) { Toast.makeText(context, "error", Toast.LENGTH_LONG).show();
}
}
答案 1 :(得分:-1)
您必须startActivity
使用Intent.ACTION_VIEW
-
Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.setDataAndType(<your_image_uri>, "image/*");
startActivity(intent);
答案 2 :(得分:-1)
Create a chooser by using the following code. You can add it in the part where you say imageview.setonclicklistener().
Intent intent = new Intent();
// Show only images, no videos or anything else
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
// Always show the chooser (if there are multiple options available)
startActivityForResult(Intent.createChooser(intent, "Select Picture"), 1);