Question

我正在尝试将文件从我的PC发送到android 对于PC我正在使用Python套接字服务器代码，要求pc用户输入路径，然后将文件发送到android mobile

然后将所选文件的位置保存为文件名变量“C：/new_image.jpg”

直到现在我已经能够发送和接收文件（PC通过Android Hotspot连接）并在android上将其保存为“temp_file”

现在我想从服务器本身接收文件名及其扩展名我试着做了

conn.send(filename)

但是在android上我在Toast中收到空值

我是这个套接字编程的新手，抱歉编程不好

这是我的Python代码

import socket,thread
from collections import deque
from Tkinter import Tk
from tkFileDialog import askopenfilename

host=socket.gethostbyname(socket.gethostname())
port=54603
s=socket.socket()
s.bind((host,port))
s.listen(5)
Tk().withdraw()
filename = askopenfilename()
print filename
print "below s.listen %s" %host
def handleclient(conn):
    f=open (filename, "rb") 
    l = f.read(1024)
    while (l):
        conn.send(l)
        l = f.read(1024)


    print "file has been sent! Now sending path of file"
    conn.send(filename)                                 #this is where null in android
    print "sent path"
    conn.close()
while True:
conn,addr=s.accept()
print 'connected to ',addr
thread.start_new_thread(handleclient,(conn,))

这是我的android接收代码

 socket = new Socket(dstAddress, dstPort);


            DataInputStream is = new DataInputStream(socket.getInputStream());

            final File f = new File(Environment.getExternalStorageDirectory() + "/"
                    + getPackageName() + "/temp_file"
            );


            File dirs = new File(f.getParent());

            if (!dirs.exists())
                dirs.mkdirs();

            f.createNewFile();
            FileOutputStream fos = new FileOutputStream(f);
            BufferedOutputStream bos = new BufferedOutputStream(fos);
            byte buf[] = new byte[10240];
            int len=0;
            while ((len = is.read(buf)) != -1)
            {
                bos.write(buf, 0, len);
                bos.flush();

            }


            fos.close();
            bos.close();

          //TIll now received the file as temp_file but not extension
          // Now next part i am trying to get extension


            result11=is.readLine();           // here reading null
           // result11=result11.substring(result11.lastIndexOf("/") + 1);

          /*  File from = new File(dirs,"temp_dhruvit");
            File to = new File(dirs,result11);
            if(from.exists())
                from.renameTo(to);
            d1.close();
            is1.close(); */

            is.close();
            socket.close();

无法在套接字编程中同时发送文件和字符串

0 个答案: