Question

noprob=["nothing","none","no damage"]

while True:
    q1=input("input your answer:")
    answer=q1.split(' ')`


    if any(a in answer for a in noprob):
        function()#wont call this
        break
    else:
        print("else statement")
        continue

def function():
    print("code now works")

我的代码不会在应该的时候调用该函数。此代码应识别用户输入并输出必要的操作。

新的整个代码：添加了elif语句，我认为这是代码的问题

`noprob=["nothing","none","no damage"]
something=["something","yes"]`

def function():
    print("code now works")`

def something():
    print("something, code works")
while True:
    q1=input("input your answer:")
    answer=q1.split(' ')`


    if any(a in answer for a in noprob):
        function()#wont call this
        break
    elif any(a in answer for a in something):
        something()
        break
    else:
        print("else statement")
        continue

Answer 1

Python从上到下执行代码。因此，如果您之前没有声明其定义，那么您将无法执行function。在while循环之前移动函数。

noprob=["nothing","none","no damage"]

def function():
    print("code now works")

while True:
    q1=input("input your answer:")
    answer=q1.split(' ')


    if any(a in answer for a in noprob):
        function()#wont call this
        break
    else:
        print("else statement")
        continue

Answer 2

您的问题是，您的列表和功能都名为something。重命名一个并相应地更改您的代码。

something=["something","yes"]

def something(): #this one shadows your list and needs to be renamed
    print("something, code works")

对于生成器，Python 3.5

python-函数不是在while循环中调用的

2 个答案: