Question

让我们说我们有一个例如来自预览问题的数组...我怎样才能找到 [X] =＆gt; stdClass对象如果我们知道这个对象的[id]是[id] =＆gt; 9 ???

Array
(
    [0] => stdClass Object
        (
            [id] => 8
            [book_category] => C Program
            [book_id] => 2
            [book_name] => C Language
            [book_category_id] => 8
            [book_in_stock] => 5
        )

    [1] => stdClass Object
        (
            [id] => 8
            [book_category] => C Program
            [book_id] => 1
            [book_name] => C++
            [book_category_id] => 8
            [book_in_stock] => 10
        )

    [X] => stdClass Object
        (
            **[id] => 9**
            [book_category] => English
            [book_id] => 3
            [book_name] => Comp Eng
            [book_category_id] => 9
            [book_in_stock] => 5
        )

    [3] => stdClass Object
        (
            [id] => 9
            [book_category] => English
            [book_id] => 4
            [book_name] => Eng English
            [book_category_id] => 9
            [book_in_stock] => 5
        )

)

Answer 1

或使用array_filter：

$result=array_filter($array, function($x) {
    return $x->id == 9;
});

将返回ID为9的所有对象。如果id是唯一的，则可以使用$result[0]访问该对象。

Answer 2

你必须走很长的路，并搜索数组的每个元素：

foreach( $array as $key => $array_element ) {
    if( $array_element-> id == 9 ) {
        // Do what you want here. The value you're looking for is in $key.
    }
}

Answer 3

在PHP 7上：

$key = array_search( 9, array_column( $array, 'id' ) );

在PHP＆lt; 7请参阅其他答案，或 - 如果您想要模拟array_column：

function array_column2( $array, $column )
{
    return array_map
    ( 
        function( $row ) use( $column )
        {
            return is_object( $row ) ? $row->$column : $row[$column];
        }
        , $array
    );
}

$key = array_search( 9, array_column2( $array, 'id' ) );

的 3v4l.org demo

详细了解array_column()

详细了解array_map()

如果你知道数组[x] - ＆gt; ID，找出数组[x]的对象id？

3 个答案: