我正在尝试为经典的啤酒瓶输出创建方法。
给定一个数字@beers
,我想将其转换为数字的单词版本。我想将数字拆分成一个数组,然后将数字列表与单词进行比较:
class BeerSong
attr_accessor :beers
def initialize(beers)
if beers > 99
beers = 99
elsif beers < 1
beers = "Zero"
end
@beers = beers
end
def worded
num_name = {
90 => "Ninety", 80 => "Eighty", 70 => "Seventy",60 => "Sixty",
50 => "Fifty",40 => "Forty",30 => "Thirty",20 => "Twenty",
19 => "Nineteen", 18 => "Eighteen", 17 => "Seventeen", 16 => "Sixteen",
15 => "Fifteen",14 => "Fourteen", 13 =>"Thirteen", 12 => "Twelve",
11 => "Eleven", 10 => "Ten", 9 => "Nine",8 => "Eight", 7 => "Seven",
6 => "Six",5 => "Five",4 => "Four",3 => "Three",2 => "Two",1 => "One"
}
worded = ""
beers = @beers
split_beers = beers.to_s.split
num_name.each do |number, name|
split_number = number.to_s.split
if beers == number
worded << name
else
number > 19 && split_number[0].to_i == split_beers[0].to_i
worded << name
worded << "-"
end
end
num_name.each do |number, name|
if number < 10 && split_beers[1].to_i == number
worded << name
end
end
worded
end
def print_song
while @beers.to_i > 2
puts "#{worded} bottles of beer on the wall,"
puts "#{worded} bottles of beer,"
puts "Take one down, pass it around,"
@beers -= 1
puts "#{worded} bottles of beer on the wall.\n\n"
end
if @beers.to_i == 2
puts "#{worded} bottles of beer on the wall,"
puts "#{worded} bottles of beer,"
puts "Take one down, pass it around,"
@beers -= 1
puts "#{worded} bottle of beer on the wall.\n\n"
end
if @beers.to_i == 1
puts "#{worded} bottle of beer on the wall,"
puts "#{worded} bottle of beer,"
puts "Take one down, pass it around,"
puts "Zero bottles of beer on the wall.\n\n"
end
if @beers.to_i == 0
print ""
end
end
end
我正在尝试比较第一个数字以获得数字,然后比较用连字符分隔的单位的第二个数字。
答案 0 :(得分:0)
你的台词:
NULL
假设一个数组结果不是这种情况,因为您没有提供要拆分的模式 所以使用默认值。请参阅:http://ruby-doc.org/core-2.0.0/String.html#method-i-split
split_beers = beers.to_s.split
split_number = number.to_s.split
最后一个是你想要的。