Question

以下是我发现的查询非常慢。

基本上我试图通过加入这三个表来获取每个workflow_id的最新状态以及其他信息。

查询逻辑如下：

按作业执行ID执行表批处理步骤，使用max（step_execution_id）检索最新步骤，然后使用步骤执行ID检索所有列
在job_instance_id上按表batch_job_execution分组并检索最新执行。
内部联接1和2基于最新步骤的最新执行和作业执行加入
加入id映射表

这是我目前的代码：

SELECT workflow_id,
       collabration_key,
       TAB3.START_TIME                 AS WORKFLOWDATE,
       batch_step_execution.STEP_NAME  AS CURRENT_STEP_NAME ,
       batch_step_execution.EXIT_CODE  AS CURRENTSTEP ,
       batch_step_execution.start_time AS STEPTIME ,
       TAB3.EXIT_CODE                  AS JOB_STATUS
FROM   batch_step_execution
       INNER JOIN (
         SELECT *
         FROM   rpx_id_mapping
                INNER JOIN (
                  SELECT batch_job_execution.job_execution_id,
                         batch_job_execution.job_instance_id ,
                         batch_job_execution.START_TIME ,
                         batch_job_execution.EXIT_CODE
                  FROM   batch_job_execution
                  WHERE  batch_job_execution.job_execution_id IN (
                           SELECT MAX(job_execution_id)
                           FROM   batch_job_execution
                           WHERE  job_instance_id IN (
                                    SELECT job_id
                                    FROM   rpx_id_mapping
                                  )
                           GROUP BY  job_instance_id
                        )
                ) TAB2
                ON rpx_id_mapping.job_id = TAB2.job_instance_id
       ) TAB3
       ON batch_step_execution.job_execution_id = TAB3.job_execution_id
WHERE  batch_step_execution.step_execution_id = (
         SELECT MAX(step_execution_id)
         FROM   batch_step_execution
         WHERE  batch_step_execution.job_execution_id = TAB3.job_execution_id
       )
) TAB4

这是表结构。

有没有更好的方法来实现同样的目标？

Answer 1

按作业执行ID和检索的表批处理步骤执行分组   最新步骤使用max（step_execution_id），然后检索所有   使用步骤执行ID的列

按表batch_job_execution分组   job_instance_id并检索最新执行。

内部联接1和2基于最新步骤的最新执行和作业执行加入

加入id映射表

我试图遵循你的逻辑并认为使用分析查询获得最大行是相同的：

SELECT *
FROM   (
    SELECT workflow_id,
           collabration_key,
           bse.START_TIME AS WORKFLOWDATE,
           bse.STEP_NAME   AS CURRENT_STEP_NAME ,
           bse.EXIT_CODE   AS CURRENTSTEP ,
           bse.start_time  AS STEPTIME ,
           bse.EXIT_CODE  AS JOB_STATUS,
           ROW_NUMBER() OVER ( PARTITION BY rim.job_execution_id,
                                            rim.job_id
                               ORDER BY     bse.step_execution_id DESC,
                                            bse.job_execution_id  DESC ) AS rn
    FROM   batch_step_execution bse
           INNER JOIN rpx_id_mapping rim
           ON (  bse.job_execution_id = rim.job_execution_id)
           INNER JOIN batch_job_execution bje
           ON ( rim.job_id = bje.job_instance_id )
)
WHERE rn = 1;

如果不是，那么希望它可以让你了解如何简化事情。

更好的写视图方法

1 个答案: