Question

我想从字符串中提取所有网址。我在this thread

中找到了完美的RegEx

现在我需要帮助来迭代所有比赛。我还看了this example（在底部），但我不能按照我想要的方式工作

基本上我想迭代所有匹配，就像第二个例子一样，我也想访问第一个例子中的子匹配（5＆amp; 8）。

目前我只获得第一场比赛。我怎么能得到余下的？

unsigned counter = 0;
std::string urls = "www.google.de/test.php&id=2#anker stackoverflow www.test.com please work example.com/test";
std::regex word_regex(
        R"(^(([^:\/?#]+):)?(//([^\/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?)",
        std::regex::extended
);
auto words_begin = std::sregex_iterator(urls.begin(), urls.end(), word_regex);
auto words_end = std::sregex_iterator();

for (std::sregex_iterator i = words_begin; i != words_end; ++i) {
    std::smatch match = *i;
    std::string match_str = match.str();
    for (const auto& res : match) {
        std::cout << counter++ << ": " << res << std::endl;
    }
    std::cout << "  " << match_str << '\n';
}

输出：

0: www.google.de/test.php&id=2#anker stackoverflow www.test.com please work example.com/test
1: 
2: 
3: 
4: 
5: www.google.de/test.php&id=2
6: 
7: 
8: #anker stackoverflow www.test.com please work example.com/test
9: anker stackoverflow www.test.com please work example.com/test
www.google.de/test.php&id=2#anker stackoverflow www.test.com please work example.com/test

RegEx查找文本中URL的所有匹配项

0 个答案: