我正在尝试将传递给python脚本的参数复制到文件中。这是参数。
f = open(in_file_name, 'w')
for x in range(5, len(arg_list)):
f.write(arg_list[x] + '\n')
f.close()
据我所知,存在缓冲问题,我的数据输入错误。但是,我无法控制传入的内容。我试图从第5个参数开始将参数复制到文件中。
P123-ND 10Q
10Q H??C
该文件的结果如下:
P123-ND
10Q
这应该是:
#!/bin/python
class Argument_Indices:
PRINTER_INDEX = 0
AREA_INDEX = 1
LABEL_INDEX = 2
EMAIL_INDEX = 3
RUN_TYPE_INDEX = 4
import argparse
import json
import os
from subprocess import call
import sys
from time import strftime
def _handle_args():
''' Setup and run argpars '''
parser = argparse.ArgumentParser(description='Set environment variables for and to call Program')
parser.add_argument('time_to_run', default='NOW', choices=['NOW', 'EOP'], help='when to run the report')
parser.add_argument('arguments', nargs='+', help='the remaining command line arguments')
return parser.parse_args()
def _proces_program(arg_list):
time_stamp = strftime("%d_%b_%Y_%H_%M_%S")
printer = arg_list[Argument_Indices.PRINTER_INDEX]
area = arg_list[Argument_Indices.AREA_INDEX]
label = arg_list[Argument_Indices.LABEL_INDEX]
in_file_name = "/tmp/program{0}.inp".format(time_stamp)
os.environ['INPUT_FILE'] = in_file_name
f = open(in_file_name, 'w')
for x in range(5, len(arg_list)):
f.write(arg_list[x])
f.close()
call(['./Program.bin', printer, area, label])
os.remove(in_file_name)
def main():
''' Main Function '''
arg_list = None
args = _handle_args()
if len(args.arguments) < 1:
print('Missing name of input file')
return -1
with open(args.arguments[0]) as input_file:
arg_list = json.load(input_file)
_process_program(arg_list)
return 0
if __name__ == '__main__':
if main() != 0:
print('Program run failed')
sys.exit()
我怎能不包含不良数据?有效信息和不良信息之间的空间发生了什么?
根据要求,这是完整的程序:
$scope.gridData.data([]);
答案 0 :(得分:0)
对于您的确切情况(您收到重复参数并且中间有一些空格),这样可行:
received_param_list = ["0013","1","1","\"john.dow@gmail.com\"","1","P123-ND 10Q","10Q H??C"]
arg_list = [i.split(" ")[0] for i in received_param_list]
last_param = received_param_list[-1].split()[-1]
if last_param != arg_list[-1]:
arg_list.append(last_param)
for x in range(5, len(arg_list)):
print (arg_list[x])
虽然可能有另一种更简单的方式