Question

我已覆盖getParams()，mEmail，mUsername等已全局声明。

@Override
public Map<String, String> getParams() throws AuthFailureError {
    Map<String,String> params = new Hashtable<String, String>();

    params.put("Email", mEmail.getText().toString().trim());
    params.put("Username",mUsername.getText().toString().trim());
    params.put("Password",mPassword.getText().toString().trim());
    params.put("BirthDay",mBirthday.getText().toString().replaceAll("\\s","-"));
    params.put("Sex",SelectedRadio());
    params.put("Bitmap",getEncodedBitmap());

    return params;
}

这是我的服务器端代码：

<?php
require "init1.php";

$email = $_POST["Email"];
$password = $_POST["Password"];
$Username  = $_POST["Username"];
$Sex = $_POST["Sex"];
$ProfilePicture = $_POST["Bitmap"];

$timestamp = strtotime($_POST["BirthDay"]);
$BirthDay = date('Y-m-d',$timestamp);

$sql = "select * from Registered_Users where Username='$Username'";
$sqle = "select * from Registered_Users where Email='$email'";
try{
    $result1 = mysqli_query($con, $sqle) or die(mysqli_error($con));;
    $result = mysqli_query($con, $sql) or die(mysqli_error($con));;
} catch(Exception $e) {
    echo $e->getMessage();
}

if (mysqli_num_rows($result) > 0){
    $myclass = new stdClass();
    $myclass->status="Not Ok";

    echo json_encode($myclass);
} else if(mysqli_num_rows($result1) > 0) {
    $myclass = new stdClass();
    $myclass->status="Not Ok";

    echo json_encode($myclass);
} else{
    try{
        $sql_query = "insert into Registered_Users (Email, Password, BirthDay, Sex, Username, ProfilePicture) values('$email', '$password', '$BirthDay', '$Sex', '$Username', '$ProfilePicture')";

        if(mysqli_query($con,$sql_query)){
            $obj1 = new stdClass();
            $obj1->status="Ok";

            echo json_encode($obj1);
        } else {
            $obj1 = new stdClass();
            $obj1->status="Not Ok ";
        }
    } catch(Exception $e) {
        echo $e->getMessage();
    }
}
?>

我得到的响应总是not ok，因为我的数据库中已经有一个空行，我正在尝试再次上传一个空行。有人能说出为什么我无法获取数据吗？为什么我得到空数据？

Answer 1

使用此自定义排球请求类

import com.android.volley.NetworkResponse;
import com.android.volley.ParseError;
import com.android.volley.Request;
import com.android.volley.Response;
import com.android.volley.Response.ErrorListener;
import com.android.volley.Response.Listener;
import com.android.volley.toolbox.HttpHeaderParser;

import org.json.JSONException;
import org.json.JSONObject;

import java.io.UnsupportedEncodingException;
import java.util.Map;

public class CustomJsonRequest extends Request<JSONObject> {

    private Listener<JSONObject> listener;
    private Map<String, String> params;

    public CustomJsonRequest(String url, Map<String, String> params,
                             Listener<JSONObject> reponseListener, ErrorListener errorListener) {
        super(Method.GET, url, errorListener);
        this.listener = reponseListener;
        this.params = params;
    }

    public CustomJsonRequest(int method, String url, Map<String, String> params,
                             Listener<JSONObject> reponseListener, ErrorListener errorListener) {
        super(method, url, errorListener);
        this.listener = reponseListener;
        this.params = params;
    }

    @Override
    protected Map<String, String> getParams() throws com.android.volley.AuthFailureError {
        return params;
    }

    ;

    @Override
    protected Response<JSONObject> parseNetworkResponse(NetworkResponse response) {
        try {
            String jsonString = new String(response.data,
                    HttpHeaderParser.parseCharset(response.headers));
            return Response.success(new JSONObject(jsonString),
                    HttpHeaderParser.parseCacheHeaders(response));
        } catch (UnsupportedEncodingException e) {
            return Response.error(new ParseError(e));
        } catch (JSONException je) {
            return Response.error(new ParseError(je));
        }
    }

    @Override
    protected void deliverResponse(JSONObject response) {
        // TODO Auto-generated method stub
        listener.onResponse(response);
    }
}

您可以将其与

一起使用

Map<String,String> params = new Hashtable<String, String>();

params.put("Email", mEmail.getText().toString().trim());
params.put("Username",mUsername.getText().toString().trim());
params.put("Password",mPassword.getText().toString().trim());
params.put("BirthDay",mBirthday.getText().toString().replaceAll("\\s","-"));
params.put("Sex",SelectedRadio());
params.put("Bitmap",getEncodedBitmap());



CustomJsonRequest request = new CustomJsonRequest(Request.Method.POST, url, params,
        new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {

            }
        }, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError error) {

    }
});

request.setRetryPolicy(new DefaultRetryPolicy(DefaultRetryPolicy.DEFAULT_TIMEOUT_MS * 2, DefaultRetryPolicy.DEFAULT_MAX_RETRIES, DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));
AppController.getInstance().getRequestQueue().add(request);

实际上这是一个与凌空发送参数的问题。检查这个答案 https://stackoverflow.com/a/27091088/1320616

编辑：此行为的说明

你的JsonObjectRequest类是从JsonRequest扩展而来的，它扩展自Request。

在Request类中有一个方法

/**
     * Returns the raw POST or PUT body to be sent.
     *
     * <p>By default, the body consists of the request parameters in
     * application/x-www-form-urlencoded format. When overriding this method, consider overriding
     * {@link #getBodyContentType()} as well to match the new body format.
     *
     * @throws AuthFailureError in the event of auth failure
     */
    public byte[] getBody() throws AuthFailureError {
        Map<String, String> params = getParams();
        if (params != null && params.size() > 0) {
            return encodeParameters(params, getParamsEncoding());
        }
        return null;
    }

注意此方法正在调用getParams（）方法。这与您在拨打电话时重写的方法相同。

但是如果你看一下JsonRequest类，就有一个方法

@Override
    public byte[] getBody() {
        try {
            return mRequestBody == null ? null : mRequestBody.getBytes(PROTOCOL_CHARSET);
        } catch (UnsupportedEncodingException uee) {
            VolleyLog.wtf("Unsupported Encoding while trying to get the bytes of %s using %s",
                    mRequestBody, PROTOCOL_CHARSET);
            return null;
        }
    }

这意味着Request的getBody（）已被JsonRequest类的getBody（）覆盖，这意味着你的getParams（）永远不会被调用。因此，您需要一个直接扩展Request类的自定义类，并且不会覆盖Request类的getBody（）方法。

没有为JsonObjectRequest调用Android Volley getParams（）方法

1 个答案: