Question

我需要具有给定属性ID的用户，例如Property.id = $id

我想构建此查询。

$sql = "SELECT p.address1, p.address2, p.address3, p.postcode,
               u.email, u.fullname
               c.company_name, 
               tc.created,
               tn.active
        FROM property AS p
        LEFT JOIN tenancy AS tc ON tc.property_id = p.id 
        LEFT JOIN tenant AS tn ON tn.tenancy_id = tc.id 
        LEFT JOIN users AS u ON u.id = tn.user_id 
        WHERE p.id = $id
            AND p.active = 1
            AND tc.active = 1
            AND tn.active = 1
            AND u.active = 1
        ";

这是我的协会：

// Tenants
class TenantTable extends Table
{
public function initialize(array $config)
{
    $this->table('tenant');
    $this->displayField('id');
    $this->primaryKey('id');
    $this->addBehavior('Timestamp');
    $this->belongsTo('Users', [
        'foreignKey' => 'user_id',
        'joinType' => 'INNER'
    ]);
    $this->belongsTo('Tenancies', [
        'foreignKey' => 'tenancy_id',
        'className' => 'tenancy',
        'joinType' => 'INNER'
    ]);


// Users
class UsersTable extends Table
{

public function initialize(array $config)
{
    $this->table('users');
    $this->displayField('name');

    $this->hasMany('Tenants', [
        'foreignKey' => 'user_id',
        'foreignKey' => 'tenants'
    ]);
}


// Tenancies
class TenancyTable extends Table
{

public function initialize(array $config)
{
    parent::initialize($config);

    $this->table('tenancy');
    $this->displayField('id');
    $this->primaryKey('id');

    $this->addBehavior('Timestamp');

    $this->belongsTo('Properies', [
        'foreignKey' => 'property_id',
        'className' => 'property'
    ]);

    $this->belongsTo('Company', [
        'foreignKey' => 'company_id'
    ]);

    $this->hasMany('Tenant', [
        'foreignKey' => 'tenancy_id',
        'className' => 'tenant'
    ]);


// Properties
class PropertyTable extends Table
{

public function initialize(array $config)
{
    parent::initialize($config);

    $this->table('property');
    $this->displayField('id');
    $this->primaryKey('id');

    $this->addBehavior('Timestamp');

    $this->belongsTo('Company', [
        'foreignKey' => 'company_id'
    ]);

    $this->hasMany('Tenancies', [
        'foreignKey' => 'property_id',
        'className' => 'tenancy'
    ]);
}

我可以获得hasMany关联，但是当它为用户获取belongsTo时，它告诉我租户与用户没有关联。如何设置关联并且它们是正确的。我正在从PropertyTable运行以下ORM。

$query = $this->find()
            ->select([ 
                'Property.id', 'Property.company_id', 'Property.address1', 'Property.address2', 'Property.address3','Property.postcode',
                'Tenancies.id', 'Tenancies.property_id', 'Tenancies.created', 'Tenancies.stage', 'Tenancies.landlord_offer_sent',
                'Company.id', 'Company.company_name',
                'Tenants.id', 'Tenants.user_id', 'Tenants.stage', 
                'Users.id', 'Users.email', 'Users.fullname'
            ])
            ->where(['Property.id' => $id])
            ->contain(['Company', 'Tenancies'])
            ->leftJoinWith('Tenancies', function(\Cake\ORM\Query $query) {
                return $query->where([
                    'Tenancies.active' => 1,
                ]);
            })
            ->contain(['Tenancies.Tenants'])
            ->leftJoinWith('Tenancies.Tenants', function(\Cake\ORM\Query $query) {
                return $query->where([
                    'Tenants.active' => 1,
                ]);
            }) 
 /*======= The problem starts from here  =========*/        
            ->contain(['Tenancies.Tenants.Users'])
            ->leftJoinWith('Tenancies.Tenants.Users', function(\Cake\ORM\Query $query) {
                return $query->where([
                    'Users.active' => 1,
                ]);
            });

任何帮助pelase

Answer 1

根据您提供的内容，您有以下关系：

属性hasMany Tenancies hasMany Tenants areTo Users 属性属于公司

假设您已在表类中进行了设置，则可以使用与上述类似的包含的联接：

public function getExample($id) {
    return $this->find()
    ->contain([
        'Company' => function ($q) {
            return $q
                ->select(['id', 'company_name'])
                ->where(['Company.active = 1']);
        },
        'Tenancies' => function($q) {
            return $q
                ->select(['Tenancies.id','Tenancies.property_id','Tenancies.created',
                    'Tenancies.stage','Tenancies.landlord_offer_sent',
                    'Tenants.id','Tenants.stage', 'Tenants.user_id', 'Tenants.tenancy_id',
                    'Users.id', 'Users.email', 'Users.fullname'
                ])->leftJoin(['Tenants' => 'tenant'],[
                    'Tenants.tenancy_id = Tenancies.id'
                ])->leftJoin(['Users' => 'users'],[
                    'Users.id = Tenants.user_id'
                ])
                ->where([
                    'Tenancies.active = 1',
                    'Tenants.active = 1',
                    'Users.active = 1',
                ]);
        }
    ])
    ->where(['Property.active = 1', 'Property.id' => $id])
    ->toArray();
}

belongsTo如何与多个hasMany一起使用包含cakephp 3.x.

1 个答案: