我已经在这个应用程序的建模和初始种子过程中挣扎了一段时间了。我想在EventArtist
和Event
之间制作一个联合表格Artist
,这样就可以检索出任何活动的所有艺术家的阵容和所有活动艺术家参与了。如何在一个活动中添加多个artist_id
?
这是种子文件:
venue = Venue.create(name: "Speakeasy", address: "Lynwood Ave", zip_code: "30312")
artist = Artist.create(name: "DJ Sliink", bio: "jersey club king")
artist2 = Artist.create(name: "DJ Spinn", bio: "Teklife's chief spokesperson")
#this is probably wrong
lineup = EventArtist.create({artist_id: artist.id}, {artist_id: artist2.id})
event = Event.create(name: "Dance your ass off",
date: DateTime.new(2016,2,3,10,0,0,'+7'),
venue: venue,
#this right here... how?
artist_id: ,
description: "free free free")
这里是架构的相关部分
create_table "event_artist", id: false, force: :cascade do |t|
t.integer "artist_id"
t.integer "event_id"
end
add_index "event_artist", ["artist_id"], name: "index_event_artist_on_artist_id", using: :btree
add_index "event_artist", ["event_id"], name: "index_event_artist_on_event_id", using: :btree
create_table "events", force: :cascade do |t|
t.string "name"
t.datetime "date"
t.text "description"
t.datetime "created_at", null: false
t.datetime "updated_at", null: false
t.integer "venue_id"
end
add_index "events", ["venue_id"], name: "index_events_on_venue_id", using: :btree
模特:
class Event < ApplicationRecord
belongs_to :venue
has many :artists, through :event_artists
end
class EventArtist < ApplicationRecord
belongs_to :event
belongs_to :artist
end
class Artist < ApplicationRecord
has_many :events, through: :event_artists
end
答案 0 :(得分:1)
这里的问题是艺术家通过创建EventArtists与事件相关联,而不是通过将artist_id添加到Event。
首先,我们需要声明一个Event有EventArtists。将has_many:event_artists添加到您的事件模型中。
在种子文件中,在创建活动时删除artist_id。
event = Event.create(name: "Dance your ass off",
date: DateTime.new(2016,2,3,10,0,0,'+7'),
venue: venue,
description: "free free free")
您可以通过创建EventArtist
将艺术家与该活动相关联EventArtist.create(event_id: event.id, artist_id: artist.id)
由于rails知道事件,event_artists和艺术家之间的关联,所以以下所有内容都做同样的事情:
event.event_artists.create({artist_id: artist.id}, {artist_id: artist2.id})
event.event_artists.create({artist: artist}, {artist: artist2})
artist.event_artists.create({event_id: event.id})
artist.event_artists.create({event: event})
现在你可以做像
这样的事情lineup = event.artists
- 或 -
artist_events = artist.events
答案 1 :(得分:0)
您需要在EventArtist中为每位艺术家制作单独的记录。由于你有一个has_many通过关联,这将允许你说event.artists
并返回该事件中的所有艺术家。但是每个人都需要它自己的EventArtist记录,其中一个artist_id
和event_id
您还需要在创建任何Event
EventArtist
答案 2 :(得分:0)
您需要将此添加到两个模型中:
has_many :event_artists
模型如此:
class Event < ApplicationRecord
belongs_to :venue
has_many :artists, through: :event_artists
has_many :event_artists
end
class EventArtist < ApplicationRecord
belongs_to :event
belongs_to :artist
end
class Artist < ApplicationRecord
has_many :events, through: :event_artists
has_many :event_artists
end
所以你可以播种:
event = Event.create(name: "Dance your ass off",
date: DateTime.new(2016,2,3,10,0,0,'+7'),
venue: venue,
artists: [artist, artist2],
description: "free free free")
或
event = Event.create(name: "Dance your ass off",
date: DateTime.new(2016,2,3,10,0,0,'+7'),
venue: venue,
description: "free free free")
event.artists << artist
event.artists << artist2
两者都有效。祝你好运;)