我有一个HTML文档如下:
<h1> Name of Article </h2>
<p>First Paragraph I want</p>
<p>More Html I'm interested in</p>
<h2> Subheading in the article I also want </h2>
<p>Even more Html i want to pull out of the document.</p>
<h2> References </h2>
<p>Html I do not want...</p>
我不需要文章的参考资料,我想在第二个h2标签处切片。
显然我可以找到像这样的h2标签列表:
soup = BeautifulSoup(html)
soupset = soup.find_all('h2')
soupset[1] #this would get the h2 heading 'References' but not what comes before it
我不想获得h2标签列表,我想在第二个h2标签上切片文档,并将上述内容保存在一个新变量中。基本上我想要的输出是:
<h1> Name of Article </h2>
<p>First Paragraph I want<p>
<p>More Html I'm interested in</p>
<h2> Subheading in the article I also want </h2>
<p>Even more Html i want to pull out of the document.</p>
最好的办法是什么才能做到这一点&#34;切割&#34; /切割HTML文档而不是简单地找到标签并输出标签本身?
答案 0 :(得分:1)
你可以remove/extract&#34;参考&#34;的每个兄弟元素。元素和元素本身:
public FileContentResult GetImage(int id)
{
Photo photo = context.FindPhotoById(id);
if (photo.PhotoFile != null)
{
return File(photo.PhotoFile, photo.ImageMimeType);
}
else
{
return null;
}
}
打印:
import re
from bs4 import BeautifulSoup
data = """
<div>
<h1> Name of Article </h2>
<p>First Paragraph I want</p>
<p>More Html I'm interested in</p>
<h2> Subheading in the article I also want </h2>
<p>Even more Html i want to pull out of the document.</p>
<h2> References </h2>
<p>Html I do not want...</p>
</div>
"""
soup = BeautifulSoup(data, "lxml")
references = soup.find("h2", text=re.compile("References"))
for elm in references.find_next_siblings():
elm.extract()
references.extract()
print(soup)
答案 1 :(得分:0)
您可以在字符串中找到h2
的位置,然后通过它找到子字符串:
last_h2_tag = str(soup.find_all("h2")[-1])
html[:html.rfind(last_h2_tag) + len(last_h2_tag)]