Question

我正在尝试在一个命令行中创建一个add .，commit和push的任务，例如：gulp gitsend -m "My changes"

var gulp = require('gulp');
var argv = require('yargs').argv;
var git = require('gulp-git');

gulp.task('gitsend', function() {
if (argv.m) {
    console.log('adding, commiting and pushing to git...');
    return gulp.src('.')
    .pipe(git.add())
    .pipe(git.commit(argv.m)
    .pipe(git.push('origin', 'master', function (err) {
        if (err) throw err;
    })));
}
});

但这不起作用：它引发了一个异常：

/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:623
    var written = dest.write(chunk);
                       ^
TypeError: undefined is not a function
    at write (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:623:24)
    at flow (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:632:7)
    at DestroyableTransform.pipeOnReadable (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:664:5)
    at DestroyableTransform.emit (events.js:104:17)
    at emitReadable_ (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:448:10)
    at emitReadable (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:444:5)
    at readableAddChunk (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:187:9)
    at DestroyableTransform.Readable.push (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_readable.js:149:10)
    at DestroyableTransform.Transform.push (/Users/me/myproj/front/node_modules/gulp-git/node_modules/through2/node_modules/readable-stream/lib/_stream_transform.js:145:32)
    at Array.forEach (native)

知道什么是错的，我如何存档我的需求？谢谢。

Answer 1

您可以将各个任务拆分（添加，提交，推送），然后使用run-sequence运行它们，以确保在推送之前先完成添加和提交。

var gulp = require('gulp');
var argv = require('yargs').argv;
var git = require('gulp-git');
var runSequence = require('run-sequence');

gulp.task('init', function() {
  console.log(argv.m);
});

gulp.task('add', function() {
  console.log('adding...');
  return gulp.src('.')
    .pipe(git.add());
});

gulp.task('commit', function() {
  console.log('commiting');
  if (argv.m) {
    return gulp.src('.')
      .pipe(git.commit(argv.m));
  }
});

gulp.task('push', function(){
  console.log('pushing...');
  git.push('origin', 'master', function (err) {
    if (err) throw err;
  });
});

gulp.task('gitsend', function() {
  runSequence('add', 'commit', 'push');
});

使用GULP-GIT一次添加，提交和推送

1 个答案: