我在脚本中实现了以下代码示例,该脚本遍历结果数组并为每个结果发出http请求。
function sequence(array, callback) {
return array.reduce(function chain(promise, item) {
return promise.then(function () {
return callback(item);
});
}, Promise.resolve());
};
var products = ['sku-1', 'sku-2', 'sku-3'];
sequence(products, function (sku) {
return getInfo(sku).then(function (info) {
console.log(info)
});
}).catch(function (reason) {
console.log(reason);
});
function getInfo(sku) {
console.log('Requested info for ' + sku);
//assume this function makes an http request and returns a promise
}
一旦处理了数组中的所有项目,脚本就不会退出。我如何调整它以便发生这种情况?
我的实现进行API调用并返回一个promise:
....
}).then(function(results){
sequence(results, function(result){
checkSpam(result).then(function(akismet){
if(akismet) {
//console.log('spam returned from checkspam');
write_spam_to_file(result);
} else {
//console.log('no spam returned from checkspam');
}
})
});
}).catch(function (e) {
console.log('Error occurred:');
console.log(e);
});
function sequence(array, callback) {
return array.reduce(function chain(promise, item) {
return promise.then(function () {
return callback(item);
});
}, Promise.resolve());
}
function checkSpam(entry) {
var akismetPromise = new Promise(function resolver(resolve, reject) {
akismet.checkSpam({
user_agent: 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:40.0) Gecko/20100101 Firefox/40.1',
referrer: 'http://google.com',
user_ip: entry.ip,
comment_author: entry.poster,
comment_content: entry.message,
comment_type: 'forum-post'
}, function (err, spam) {
if (err) reject(err);
resolve(spam);
});
});
return akismetPromise;
}
答案 0 :(得分:3)
与您的第一个代码段相反,您的实际代码缺少一堆return
个关键字:
…
}).then(function(results) {
return sequence(results, function(result) {
// ^^^^^^
return checkSpam(result).then(function(akismet) {
// ^^^^^^
if (akismet) {
return write_spam_to_file(result);
// ^^^^^^ // assuming the write is asynchronous and returns a promise?
}
});
});
}) …
如果您不是always return a promise来自异步函数(包括then
回调),则承诺链不知道要等待什么,并执行下一个回调而无需等待任何结果。