Question

我想将一个sql参数从用户表单传递到我的报表类但它不起作用并且它不会创建报表，当我在向报表类添加ID参数后再次打开报表设计器选项卡时，它会刷新报表并删除我的组件。

有什么问题？

这是我的报告类：

public SodoorZemanatName(long ID)
    {
        InitializeComponent(ID);
    }

    protected override void Dispose(bool disposing)
    {
        if (disposing && (components != null))
        {
            components.Dispose();
        }
        base.Dispose(disposing);
    }

    #region Designer generated code
    private void InitializeComponent(long ID)
    {
            this.components = new System.ComponentModel.Container();
            DevExpress.DataAccess.Sql.CustomSqlQuery customSqlQuery1 = new DevExpress.DataAccess.Sql.CustomSqlQuery();
            DevExpress.DataAccess.Sql.QueryParameter queryParameter1 = new DevExpress.DataAccess.Sql.QueryParameter();
            System.ComponentModel.ComponentResourceManager resources = new System.ComponentModel.ComponentResourceManager(typeof(SodoorZemanatName));
            this.topMarginBand1 = new DevExpress.XtraReports.UI.TopMarginBand();
            this.detailBand1 = new DevExpress.XtraReports.UI.DetailBand();
            this.bottomMarginBand1 = new DevExpress.XtraReports.UI.BottomMarginBand();
            this.sqlDataSource2 = new DevExpress.DataAccess.Sql.SqlDataSource(this.components);
            ((System.ComponentModel.ISupportInitialize)(this)).BeginInit();
            this.topMarginBand1.HeightF = 100F;
            this.topMarginBand1.Name = "topMarginBand1";
            this.detailBand1.HeightF = 100F;
            this.detailBand1.Name = "detailBand1";
            this.bottomMarginBand1.HeightF = 100F;
            this.bottomMarginBand1.Name = "bottomMarginBand1";
            this.sqlDataSource2.ConnectionName = "Context";
            this.sqlDataSource2.Name = "sqlDataSource2";
            customSqlQuery1.Name = "Query";
            queryParameter1.Name = "ID";
            queryParameter1.Type = typeof(long);
            queryParameter1.ValueInfo = "0";
            queryParameter1.Value = ID;
            customSqlQuery1.Parameters.Add(queryParameter1);
            customSqlQuery1.Sql = "select * from LG_Garanti where ID=@ID";
            this.sqlDataSource2.Queries.AddRange(new DevExpress.DataAccess.Sql.SqlQuery[] {
            customSqlQuery1});
            this.sqlDataSource2.ResultSchemaSerializable = resources.GetString("sqlDataSource2.ResultSchemaSerializable");
    this.Bands.AddRange(new DevExpress.XtraReports.UI.Band[] {
    this.topMarginBand1,
    this.detailBand1,
    this.bottomMarginBand1});
    this.ComponentStorage.AddRange(new System.ComponentModel.IComponent[] {
    this.sqlDataSource2});
    this.DataSource = this.sqlDataSource2;
    this.Version = "15.2";
    ((System.ComponentModel.ISupportInitialize)(this)).EndInit();
}
#endregion

这是我的呼唤：

SodoorZemanatName report = new SodoorZemanatName(1);
ASPxDocumentViewer1.ReportTypeName = "SodoorZemanatName";
ASPxDocumentViewer1.Report = report;

Answer 1

我猜你想（1）点击按钮，（2）传递一个ID然后（3）打开报告，内容取决于该ID。所以这就是我做的方式，（我不确定是否还有其他办法，因为devexpress不是开源的）：

设计数据集，它仅包含您要使用Visual Studio数据集工具显示的信息。 ie id，name，address，..... namet that dataset = ReportDataset。该数据集有一个名为MyTable的表。
使用GUI工具设计名为MyReport的报告（记住选择XtraReport），然后选择datasource = ReportDataset，不要编辑GUI工具生成的代码。只需使用GUI，点击＆amp;单击以添加标签，从ReportDataset添加值。

在你的表单，窗口表格或其他内容中，下面应该在button_click事件触发的函数内（你在问题的最后片段中的“调用”）：

DataSet new_ds = new DataSet();
ReportDataset.MyTable runtime_data = new ReportDataset.MyTable();
//get data from your database according to ID, Row by row 
//then add them to the runtime_data table
//in your case, add all the result of "select * from LG_Garanti where ID=@ID";
runtime_data.Rows.Add(new object[] {.blah blah..});// just add row, use whatever method you like
new_ds.Tables.Add(runtime_data);
//from this point, new_ds contains runtime data of the row(s) you want ID.
//now just link that dynamic dataset to your designed report
MyReport my_report = new MyReport();
my_report.DataSource = new_ds;
// Show the print preview or do whatever you want 
ReportPrintTool printTool = new ReportPrintTool(my_report);
printTool.ShowRibbonPreviewDialog();

以上是为了使其更加灵活，因为报告可以使用自己的数据集与不同表格的混合，....您可以通过在步骤1中重用自己的数据集来简化它。希望这会有所帮助。

将sql参数值传递给devexpress报告？

1 个答案: