Question

我正在尝试编写一个可以保存对文件的响应的GET处理程序。

public String get(String[] args) throws IOException {
  URL url = new URL(args[1]);
  BufferedReader input = new BufferedReader(new InputStreamReader(url.openStream()));
  String output = "";
  String line = input.readLine();
  while(line != null){
    output += line + "\n";
    line = input.readLine();
  }
  saveGetToFile(output);
  return "Response saved to: " + path.toString();
}

然而，它似乎总是两次返回响应。我在这里缺少一些逻辑吗？它返回整个响应，然后再返回整个响应。

Answer 1

由于我们不知道saveGetToFile(String)做了什么，以及path变量包含什么，我们无法知道这些行中会发生什么。但是你的代码在那时很好，除了你忘了关闭流。

public String get() throws IOException {
    URL url = new URL("http://httpbin.org/get");
    StringBuilder builder = new StringBuilder();
    BufferedReader reader = null;
    try {
        reader = new BufferedReader(new InputStreamReader(url.openStream()));
        String line;
        while ((line = reader.readLine()) != null) {
            builder.append(line).append("\n");
        }
    } finally {
        if (reader!=null) {
            reader.close();
        }
    }
    saveGetToFile(builder.toString()); //Does this method modify the value of your variable 'path'?
    return "Response saved to: " + path.toString(); //Where do you write to path?
}

如果需要，请设置System.out.println(builder.toString())以验证代码在此之前有效。

Answer 2

试一下，看看它是否有效

public String get(String[] args) throws IOException {
    URL url = new URL(args[1]);
    BufferedReader input = new BufferedReader(new   InputStreamReader(url.openStream())); 
    String output = "";
    String line;

    while((line=input.readLine())!= null){
        output += line + "\n";
    }

    saveGetToFile(output);
    return "Response saved to: " + path.toString();
}

Java GET请求返回响应两次

2 个答案: