Question

我正在使用以下Flask代码来流式传输命令的输出：

@app.route('/', methods=['GET', 'POST'])
def index():
    if request.method == 'POST':
        ...
        # some logic to get cmd from POST request
        ...
        return redirect_to(url_to(stream, cmd=cmd))
    return render_template('index.html')

@app.route('/stream/<cmd>')
def stream(cmd):
    print("Executing %s" % cmd)
    g = proc.Group()
    p = g.run(cmd)
    def stream_cmd():
        while g.is_pending():
            lines = g.readlines()
            for proc, line in lines:
                print(line)
                yield line + '</br>'
    return Response(stream_cmd(), mimetype='text/html')  # text/html is required for most browsers to show th$

当我发布我的表单时，它会重定向到一个空白页面，在那里我看到了我的流的输出，但是我放弃了所有的布局/ css / html / etc ......

如何在仍然看到流式输出的同时保持当前布局？

理想情况下，我希望能够动态地更新当前页面中的<div>元素（而不是重定向），但是我不确定＆＃＃39;甚至可能。

Answer 1

按照@reptilicus推荐，我重写了代码以使用websockets。

以下是工作代码：

<强>的Python

@socketio.on('message', namespace='/stream')
def stream(cmd):
    # Streams output of a command
    from shelljob import proc
    g = proc.Group()
    p = g.run(cmd)
    while g.is_pending():
        lines = g.readlines()
        for proc, line in lines:
            send(line, namespace='/stream')
            eventlet.sleep(0) # THIS IS MANDATORY

接收send次呼叫发送的邮件的相应JavaScript如下：

JavaScript（JQuery）

var socket = io.connect('http://' + document.domain + ':' + location.port + '/stream')

socket.on('message', function(msg){
  $('#streaming_text').append(msg);
})

...

jqxhr.done(function(cmd){ # This is executed after an AJAX post, but you can change this to whatever event you like
  socket.send(cmd)
  return false; 
})

Flask - 流内容保持上下文

1 个答案: