Question

我试图在文本文件中为每一行找到同一行的数字平均值。例如，如果这是文本文件：

8.7 6.5 0.1 3.2 5.7 9.9 8.3 6.5 6.5 1.5
0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0
1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0

我想打印像：

For Competitor #1, the average is 5.8625
For Competitor #2, the average is 0.0000
For Competitor #3, the average is 1.0000

这是我的代码。

import java.io.*;
import java.util.*;
import java.text.*;
public class BaseClass
{
    public static void main(String args[]) throws IOException
{
    NumberFormat fmt = NumberFormat.getNumberInstance();
    fmt.setMinimumFractionDigits(4);
    fmt.setMaximumFractionDigits(4);
    Scanner sf = new Scanner(new File("C:\\temp_Name\\DataGym.in.txt"));
    int maxIndx = -1;
    String text[] = new String[1000];

    while (sf.hasNext()) {
        maxIndx++;
        text[maxIndx] = sf.nextLine();
    }
    sf.close();
    int contestant = 0;

    for (int j = 0; j <= maxIndx; j++) {
        Scanner sc = new Scanner(text[j]);
        double scoreAverage = 0;
        double a = 0;
        double array[] = new double[1000];
        contestant++;
        if (j <= 10) {
            a += sc.nextDouble();
            array[j] += a;
        } else {
            Arrays.sort(array);
            int i = 0;
            while (i < 10) {
                scoreAverage += array[i];
                i++;
            }
        }

            String s = fmt.format(scoreAverage);
            double d = Double.parseDouble(s);
         System.out.println("For Competitor #" + contestant + ", the average is " + d);
    }
    }
}

打印

For the Competitor #1, the average is 0.0
For the Competitor #2, the average is 0.0
For the Competitor #3, the average is 0.0

Answer 1

你这里的问题太复杂了。以下片段足以让您实现您想要实现的目标。

以下是代码段：

public static void main (String[] args) throws Exception
{
    Scanner in = new Scanner(new File("C:\\temp_Name\\DataGym.in.txt"));
    int counter = 0;
    String line = null;
    while(in.hasNext()) {
        line = in.nextLine();
        double sum = 0;
        String[] splits = line.split(" ");
        for(String s : splits) {
            sum += Double.parseDouble(s);
        }
        System.out.println("For Competitor #" + (++counter) 
                           + ", the average is " + (sum/splits.length));
    }
}

输出：

For Competitor #1, the average is 5.69
For Competitor #2, the average is 0.0
For Competitor #3, the average is 1.0

从文本文件中查找平均值

1 个答案: