Question

例如，我从网址

中抓取这些行

wget -qO- http://superman.com/installer/ | grep "something" 

    href="Superman-Linux-20.0.1222.x64.sh"
    href="Superman-Linux-10.0.1222.x64.sh/*fingerprint*/"
    href="Superman-Linux-10.0.1222.x64.sh/*view*/"

我只想grep

Superman-Linux-20.0.1222.x64.sh

然后我需要忘记那个

wget http://superman.com/installer/Superman-Linux-20.0.1222.x64.sh

Answer 1

而不是像这样的grep：egrep -o "Superman-Linux.*\.sh"

一行代表：

wget http://superman.com/installer/$(wget -qO- http://superman.com/installer/ | egrep -o "Superman-Linux.*\.sh")

grep这个字符串的第一行并将其保存在一个变量中以进行wget它？

1 个答案: