在模板

Question

我在Django中很新... 我的问题：如何通过listView在模板中获取“自我外键”名称？ 感谢...

models.py

class Organization(Model.models):
    name = models.CharField(max_length=100)
    mother_organization = models.ForeignKey('self',
                                            null=True,
                                            blank=True,
                                            related_name='mother'
                                            )

views.py

class List(ListView):
    model = Organization
    context_object_name = "organizations"
    template_name = "organizations.html"

organizations.html

{% for organization in organizations %}
    <p>
        {{ organization.reference }}
        {{ organization.name }}
        test 0 : OK !!
        {{ organization.mother_organization.name|default:"-" }}
        test 1 : FAIL
        {{ organization.mother.name|default:"-" }}
        test 2 : FAIL
        {% for mother in organization.mother.all %}
            {{ mother.name }}
        {% empty %}
        test 3 : FAIL
        {% for mother in organization.mother_organization.all %}
            {{ mother.name }}
        {% empty %}

            #
        {% endfor %}
    </p>
{% endfor %}

Answer 1

您的字段名称为mother_organization，因此您应在模板中使用相同的字段名称：

{{ organization.mother_organization.name|default:"-" }}