如何在一个查询中编写asc

Question

我写了这个查询，但没有成功，写作asc and跟着对方有问题。

我如何解决这个问题？

$q = "SELECT * FROM coe_courses LEFT JOIN equal_coe ON
 equal_coe.course_number=coe_courses.course_number 
LEFT JOIN student_record ON coe_courses.course_number=
student_record.course_number order by student_record.course_number asc AND student_record.id=". $_SESSION['user_id'];

Answer 1

您的SQL查询需要重新排列以使用WHERE子句，如下所示：

$q = "SELECT * FROM coe_courses 
      LEFT JOIN equal_coe ON equal_coe.course_number=coe_courses.course_number 
      LEFT JOIN student_record ON coe_courses.course_number=student_record.course_number 
      WHERE student_record.id=". $_SESSION['user_id'] ."
      order by student_record.course_number asc";