Question

我无法让脚本返回字母等级。该代码允许我输入成绩，但它不会返回字母等级。它目前没有错误，但无法返回响应。

#Given (1) score, and (2) grade
# For scores between 0.0 - 1.0, this programs prints the letter grade
# For scores enter out of the range of 0.0- 1.0 this program will print an error message
# Use try/catch exception handling to gracefully exit on values outside of the specified range

import sys


score= input ("Enter numeric value of score: ")
score = 0.0-1.0
# Convert input from default string value to integer
floatScore = float (score)
try:
     intScore = int (score)


except:
    if score > 1.0:
        print ("Bad Score")


# Use conditional loop to display letter grade based on user-supplied score


# Print letter grade


    elif 1.0 >= score>=.9:
        print ("Grade is A" + str(intScore))
    elif .9 > score>=.8:
        print ("B")
    elif .8 >score>=.7:
        print ("C")    
    elif .7 >score>=.6:
        print ("D")
    elif .6 >score>=.5:
        print ("F")

# End program

Answer 1

只有在except部分遇到错误时，才会运行脚本的try部分。将得分转换为int应该没有问题，因此脚本的其余部分永远不会执行。为什么在try-catch块中呢？如果它是0到1之间的数字而不是整数，为什么还要将它转换为int呢？

您还要将分数设置为0.0-1.0，将其重置为-1.0，覆盖用户刚刚输入的内容。这样的事情会更好。

import sys

score= input ("Enter numeric value of score: ")

try:
    score = float(score)

    if score > 1.0:
        print ("Bad Score")

    # Use conditional loop to display letter grade based on user-supplied score

    # Print letter grade
    elif 1.0 >= score>=.9:
        print ("Grade is A" + str(score))
    elif .9 > score>=.8:
        print ("B")
    elif .8 >score>=.7:
        print ("C")    
    elif .7 >score>=.6:
        print ("D")
    elif .6 >score>=.5:
        print ("F")

except ValueError:
    print("You need to input a number")

# End program

Python练习3.3完整代码

1 个答案: