如何在同一事件中创建andfire bootstrap popover?
$('.btShowWkf').mouseover(function(e){
debugger;
e.stopImmediatePropagation();
//var el= e.target;
$(this).popover({
id: "customPop",
title: "QUAD-HCM Popover",
html: true,
content: function () {
return '<span style="color:red;font-size:1.3em;">WOKFLOW</span><br><span style="color:darkgrey;">YESSSSSS.</span>';
},
container: 'body',
fontColor: "#000",
borderColor: "#000",
backgroundColor: "#000",
onCreate: null,
onVisible: null,
childToAppend: null,
keepData: false,
disableHeader: false,
trigger: "click",
placement: "top"
});
$(this).trigger('click');
myTableName.workflowLabels(null,$(this));
});
我需要使用相同的单击事件来创建和触发,因为它涉及许多行以及性能和内存,并且不希望一次附加所有弹出窗口。 感谢。
答案 0 :(得分:1)
$('.btShowWkf').mouseover(function(e){
$(this).popover({
id: "customPop",
title: "QUAD-HCM Popover",
html: true,
content: function () {
return '<span style="color:red;font-size:1.3em;">WOKFLOW</span><br><span style="color:darkgrey;">YESSSSSS.</span>';
},
container: 'body',
fontColor: "#000",
borderColor: "#000",
backgroundColor: "#000",
onCreate: null,
onVisible: null,
childToAppend: null,
keepData: false,
disableHeader: false,
placement: "top"
});
$(this).popover("show");
});