当C ++中还存在非模板函数时，调用专用模板函数

Question

在这个例子中，如何调用第二个函数？

template<class T>
T square(T a) {
    std::cout << "using generic version to square " << a << std::endl;
    return a*a;
}

/// "int" is so special -- provide a specialized function template
template<>
int square(int a) {
    std::cout << "using specialized generic version to square " << a << std::endl;
    return a*a;
}

/// and there's one more: a non-template square function for int
int square(int a) {
    std::cout << "using explicit version to square " << a << std::endl;
    return a*a;
}

提前致谢！

Answer 1

通过显式指定模板参数来调用特化：

square<int>(2);

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