Question

当我在一个可观察的列表上使用mergeDelayError来在错误输出之前执行每个observable时，我得到：

OnErrorFailedException: Error occurred when trying to propagate error to Observer.onError

代码：

return Observable.mergeDelayError(Observable.from(observableList));

我用onError的参数订阅了observable（也没有执行）。

但是，当我尝试使用onErrorResumeNext来调试它时，我发现传播可观察的错误没有引起任何问题。这里发生了什么？

return Observable.mergeDelayError(Observable.from(observableList)).onErrorResumeNext(new Func1<Throwable, Observable<? extends Pair<String, Map<Long, Set<ProgressGradedItemBL>>>>>() {
    @Override
    public Observable<? extends Pair<String, Map<Long, Set<ProgressGradedItemBL>>>> call(Throwable throwable) {
        return Observable.error(throwable);
    }
});

这是我没有onErrorResumeNext的堆栈跟踪：

rx.exceptions.OnErrorFailedException: Error occurred when trying to propagate error to Observer.onError
    at rx.observers.SafeSubscriber._onError(SafeSubscriber.java:175)
    at rx.observers.SafeSubscriber.onError(SafeSubscriber.java:97)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.drainAndComplete(OperatorMerge.java:466)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.completeInner(OperatorMerge.java:449)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.emit(OperatorMerge.java:599)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.onCompleted(OperatorMerge.java:542)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.drainAndComplete(OperatorMerge.java:472)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.completeInner(OperatorMerge.java:449)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.emit(OperatorMerge.java:614)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.onCompleted(OperatorMerge.java:542)
    at rx.internal.operators.OnSubscribeCombineLatest$MultiSourceProducer.tick(OnSubscribeCombineLatest.java:151)
    at rx.internal.operators.OnSubscribeCombineLatest$MultiSourceProducer.onCompleted(OnSubscribeCombineLatest.java:183)
    at rx.internal.operators.OnSubscribeCombineLatest$MultiSourceRequestableSubscriber.onCompleted(OnSubscribeCombineLatest.java:236)
    at rx.internal.operators.OperatorMap$1.onCompleted(OperatorMap.java:43)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.drainAndComplete(OperatorMerge.java:472)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.onCompleted(OperatorMerge.java:435)
    at rx.internal.operators.OperatorMap$1.onCompleted(OperatorMap.java:43)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.drainAndComplete(OperatorMerge.java:472)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.completeInner(OperatorMerge.java:449)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.emit(OperatorMerge.java:614)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.onCompleted(OperatorMerge.java:542)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.drainAndComplete(OperatorMerge.java:472)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.onCompleted(OperatorMerge.java:435)
    at rx.internal.operators.OperatorMap$1.onCompleted(OperatorMap.java:43)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.drainAndComplete(OperatorMerge.java:472)
    at rx.internal.operators.OperatorMerge$MergeSubscriber.completeInner(OperatorMerge.java:449)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.emit(OperatorMerge.java:614)
    at rx.internal.operators.OperatorMerge$InnerSubscriber.onCompleted(OperatorMerge.java:542)
    at rx.internal.operators.OperatorDistinctUntilChanged$1.onCompleted(OperatorDistinctUntilChanged.java:64)
    at rx.internal.operators.OperatorDoOnEach$1.onCompleted(OperatorDoOnEach.java:53)
    at rx.internal.operators.OperatorMap$1.onCompleted(OperatorMap.java:43)
    at rx.internal.operators.OperatorFilter$1.onCompleted(OperatorFilter.java:42)
    at rx.internal.operators.OperatorSubscribeOn$1$1$1.onCompleted(OperatorSubscribeOn.java:66)
    at rx.observers.SerializedObserver.onCompleted(SerializedObserver.java:99)
    at rx.observers.SerializedSubscriber.onCompleted(SerializedSubscriber.java:46)
    at rx.internal.operators.OperatorConcat$ConcatSubscriber.subscribeNext(OperatorConcat.java:158)
    at rx.internal.operators.OperatorConcat$ConcatSubscriber.completeInner(OperatorConcat.java:150)
    at rx.internal.operators.OperatorConcat$ConcatInnerSubscriber.onCompleted(OperatorConcat.java:212)
    at rx.internal.operators.OperatorDoOnEach$1.onCompleted(OperatorDoOnEach.java:53)
    at rx.internal.operators.OperatorDoOnEach$1.onCompleted(OperatorDoOnEach.java:53)
    at rx.internal.operators.OperatorMap$1.onCompleted(OperatorMap.java:43)
    at rx.internal.operators.OperatorDoOnEach$1.onCompleted(OperatorDoOnEach.java:53)

Answer 1

使用Scan( Id Name ) EntityTypeCommon( Id ScanRef ... ) Entity1Type( Id TypeEntityCommonRef ... ) Entity2Type( Id TypeEntityCommonRef ... ) Entity3Type( Id TypeEntityCommonRef ... )代替OnErrorFailedException时会引发subscribe(Action1)。此外，您似乎使用旧版本的RxJava（名称subscribe(Action1, Action1)类似于1.0.12及之前）。目前的版本是1.1.2。

Answer 2

如果你的流对Observable抛出一个未经检查的异常，则observable处理中止抛出一个OnErrorFailedException。

RxJava mergeDelayError OnErrorFailedException错误：尝试将错误传播到Observer.onError时发生

2 个答案: