我有一张表说T_myTable它有5列,并且都有一些值为true或false。
--------------------------------
col1 | col2 | col3 | col4 | col5
--------------------------------
true | false|false|true |false
false| true |false|false|false
true | false|false|true |false
false| false|false|true |false
col1 | col2 | col3 | col4 | col5
--------------------------------
2 | 3 |4 |1 |4
这里的数字是假的数字。 varchar 也是真假。
答案 0 :(得分:2)
此:
SELECT SUM(CASE WHEN Col1 = 'false' THEN 1 ELSE 0 END) AS Col1
, SUM(CASE WHEN Col2 = 'false' THEN 1 ELSE 0 END) AS Col2
, SUM(CASE WHEN Col3 = 'false' THEN 1 ELSE 0 END) AS Col3
, SUM(CASE WHEN Col4 = 'false' THEN 1 ELSE 0 END) AS Col4
, SUM(CASE WHEN Col5 = 'false' THEN 1 ELSE 0 END) AS Col5
FROM T_myTable
答案 1 :(得分:0)
试试这个:
SELECT SUM(CASE col1 WHEN 'false' THEN 1 ELSE 0 END),
SUM(CASE col2 WHEN 'false' THEN 1 ELSE 0 END),
SUM(CASE col3 WHEN 'false' THEN 1 ELSE 0 END),
SUM(CASE col4 WHEN 'false' THEN 1 ELSE 0 END),
SUM(CASE col5 WHEN 'false' THEN 1 ELSE 0 END)
FROM T_myTable
答案 2 :(得分:0)
最有趣的方式之一是:
检查一下:
SELECT [col1],[col2],[col3],[col4],[col5]
FROM (
SELECT MyVal, ColName
FROM (
SELECT *
FROM T_myTable
) AS pvt
UNPIVOT(MyVal FOR ColName IN ([col1],[col2],[col3],[col4],[col5])) AS unpvt
WHERE MyVAl = 'false'
) As DT
PIVOT (COUNT(MyVal) FOR ColName IN ([col1],[col2],[col3],[col4],[col5])) AS PT
结果:
col1 col2 col3 col4 col5
2 3 4 1 4