Question

我可以比较方法工作到Tuple9如下：

  import scala.math.Ordered.orderingToOrdered
  (1,2,"ab",4,5,6.0,7l,"de",1.0) compare (1,2,"ab",4,5,6.0,7l,"de",1.0)

但是使用Tuple10我得到了编译错误：

  import scala.math.Ordered.orderingToOrdered
  (1,2,"ab",4,5,6.0,7l,"de",1.0,2) compare (1,2,"ab",4,5,6.0,7l,"de",1.0,2) // >> compile error: value compare is not a member of (Int, Int, String, Int, Int, Double, Long, String, Double, Int)

我尝试了替代方式，但这也给出了隐含错误：

implicitly[Ordering[Tuple10[Int, Int, String, Int, Int, Double, Long, String, Double, Double]]].compare((1,2,"ab",4,5,6.0,7l,"de",1.0,4), (1,2,"ab",4,5,6.0,7l,"de",1.0,4)) 

compiler error:
No implicit Ordering defined for (Int, Int, String, Int, Int, Double, Long, String, Double, Double).
not enough arguments for method implicitly: (implicit e: Ordering[(Int, Int, String, Int, Int, Double, Long, String, Double, Double)])Ordering[(Int, Int, String, Int, Int, Double, Long, String, Double, Double)]. Unspecified value parameter e.

看起来Ordering只定义为Tuple9。如果我错了，请纠正我。

Answer 1

从source code可以看出，你是对的，它只适用于Tuple9。但是，在每次迭代中看到模式后，您应该能够根据需要进行复制和扩展。

Scala Tuple10隐式排序不起作用

1 个答案: