Question

我编码如下：

func spriteCollection(count : Int) -> [SKSpriteNode]{

    var spriteArray = [SKSpriteNode]()

    for _ in 0..<count {

        let sprite = SKSpriteNode(imageNamed: "node.png")

        //giving random position to sprites, but problem is some sprites are going invisible. How do I make it appear inside the view?

        let x = CGFloat(arc4random_uniform(UInt32(UIScreen.mainScreen().bounds.size.height)))

        let y = CGFloat(arc4random_uniform(UInt32(UIScreen.mainScreen().bounds.size.width)))

        sprite.position = CGPoint(x: x, y: y)

        spriteArray.append(sprite)

    }

    return spriteArray

}

override func didMoveToView(view: SKView) {

    let spriteCollection = spriteCollection(10)

    for sprite in spriteCollection{

        //facing problem here, not sure how to move it inside the view

        let x = CGFloat(arc4random_uniform(UInt32(size.height)))

        let y = CGFloat(arc4random_uniform(UInt32(size.width)))

        let action = SKAction.moveTo(CGPoint(x: x , y: y), duration: 5)

        sprite.runAction(action)

        addChild(sprite)
   }
}

我现在面临的问题是，如果我将计数10传递给spriteCollection，我只能看到5或6个精灵，其余全部被隐藏。我只想让所有精灵出现在屏幕尺寸内，当我执行移动动作时，它的位置也应该在屏幕内。我在横向模式下工作。谁能帮我解决这个问题..

Answer 1

您遇到的问题是屏幕的边界在处于纵向模式时面向设备，而视图的边界基于屏幕尺寸处于横向模式时。

解决问题的一种方法是在“屏幕空间”工作时撤消x和y计算

// Note how width and height appear to be "backward" here.  That's because the screen
// coordinates are defined by the portrait orientation of the device,
// but the view will eventually be in a landscape orientation

let x = CGFloat(arc4random_uniform(UInt32(UIScreen.mainScreen().bounds.size.width)))
let y = CGFloat(arc4random_uniform(UInt32(UIScreen.mainScreen().bounds.size.height)))

但我认为更好的想法是等待将精灵移动到初始位置，直到创建视图，然后根据视图的边界随机定位它们而不是屏幕的界限

如何在屏幕尺寸内显示'n'个spriteNodes并在屏幕内移动？

1 个答案: