Question

我是一名非常熟练的Android开发人员，我正在研究一个非常简单的应用程序，该应用程序从SQLite数据库中读取条目并将它们映射到ListView，只要单击“全部列出”按钮，就会显示CUSTOMER_NAME字段。我一直在关注一些不同的教程，但已经遇到了范围问题。

编辑：如何完成从光标到ListView的映射？

非常感谢您提供的任何帮助！

到目前为止，我的DBHelper，getAllCustomer方法看起来像：

public Cursor getAllCustomers(){
    List<Customer> customers=new LinkedList<Customer>();

    String query="SELECT * FROM "+TABLE_NAME;

    SQLiteDatabase db=this.getWritableDatabase();
    Cursor cursor= db.rawQuery(query, null);

    return cursor;
}

我的fragment_list.xml看起来像（参见ListView）：

<LinearLayout
    android:orientation="vertical"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:layout_alignParentTop="true"
    android:layout_centerHorizontal="true">

    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:textAppearance="?android:attr/textAppearanceLarge"
        android:text="List Customers"
        android:id="@+id/textView3"
        android:layout_gravity="center_horizontal" />

    <ListView
        android:layout_width="wrap_content"
        android:layout_height="381dp"
        android:layout_centerHorizontal="true"
        android:layout_alignParentTop="true"
        android:id="@+id/listView"
        android:layout_above="@+id/btnAdd" />

    <Button
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="List All"
        android:id="@+id/btnGetAll"
        android:layout_alignParentBottom="true"
        android:layout_toRightOf="@+id/btnAdd" />

</LinearLayout>

最后是我的CustomersFragment.java

public class CustomersFragment extends Fragment {

public CustomersFragment() {

}

public static CustomersFragment newInstance() {
    CustomersFragment fragment = new CustomersFragment();
    Bundle args = new Bundle();
    fragment.setArguments(args);
    return fragment;
}

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    View rootView = inflater.inflate(R.layout.fragment_search, container, false);
    return rootView;
}

@Override
public void onActivityCreated(Bundle savedInstanceState) {
    super.onActivityCreated(savedInstanceState);

    Button bGetAll = (Button) getActivity().findViewById(R.id.btnGetAll);
    bGetAll.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            CustomerrDBSetup db = new CustomerrDBSetup(getActivity());
            Cursor cursor = db.getAllCustomers();
            String[] from = new String[] { "customer_name" };

        }
    });
  }
}

Answer 1

你的功能应该是这样的

public List<Customer> getAllCustomers(){
    List<Customer> customers = new LinkedList<Customer>();
    String query="SELECT * FROM " + TABLE_NAME;
    SQLiteDatabase db=this.getWritableDatabase();
    Cursor cursor= db.rawQuery(query, null);

    if (cursor.moveToFirst()) {
            do {
                Customer customer = customerFromCursor(cursor);
                customers.add(cutomer);
            } while (cursor.moveToNext());
        }

    //don't forget to close cursor after use it

    if (cursor != null) {
            cursor.close();
        }

    return customers;
}


public Customer customerFromCursor(Cursor cursor){
    Customer ret = new Customer();

    //put your getter here

    //ex:
    ret.setName(cursor.getString(cursor.getColumnIndex(yourColumName)));

    //.....
    return ret;
  }

通过这种方式，您将获得listview的所有数据

带有Fragments的游标适配器和SQLite解决方案

1 个答案: