我有一个包含表格(tblPersonnel
)的数据库,其中填充了以下数据。
Name_Personnel VesselName SailoutDate Time_transfer Direction
JB Flight 2 3/03/2016 10:38:00 UP
MH Flight 2 3/03/2016 10:38:00 UP
RS Flight 2 3/03/2016 10:38:00 UP
JB Flight 2 3/03/2016 11:40:00 DOWN
MH Flight 2 3/03/2016 11:40:00 DOWN
RS Flight 2 3/03/2016 11:40:00 DOWN
我需要查询" UP"之间所有人员的总时间。和" DOWN"时间。 我希望得到这样的输出。
Name_Personnel VesselName SailoutDate Time_transfer_UP Time_transfer_DOWN Total_time
JB Flight 2 3/03/2016 10:38:00 11:40:00 01:02
MH Flight 2 3/03/2016 10:14:00 11:49:00 01:35
RS Flight 2 3/03/2016 10:36:00 11:53:00 01:17
Name_personnel
,vesselname
和sailoutdate
总是有一个" UP"和" Down"值。所以这些可以用来搜索匹配的行。
我该怎么做?
答案 0 :(得分:0)
您可以使用条件聚合。挑战是总时间。如果你可以忍受总分钟,那么这很容易:
select Name_Personnel, VesselName, SailoutDate,
max(iif(direction = 'UP', time_transfer, NULL)) as time_transfer_up,
max(iif(direction = 'DOWN', time_transfer, NULL)) as time_transfer_down,
datediff("minute",
max(iif(direction = 'UP', time_transfer, NULL))
max(iif(direction = 'DOWN', time_transfer, NULL))
) as minutes_diff
from tblPersonnel
group by Name_Personnel, VesselName, SailoutDate;
答案 1 :(得分:0)
谢谢, 两个答案都运行良好,虽然我看到不同的输出,因为并非所有数据都被完全正确填充。
我最后的询问变成了这个。
SELECT DateDiff("n",Max(IIf([direction]='UP',[time_transfer],Null)),Max(IIf([direction]='DOWN',[time_transfer],Null))) AS minutes_diff, tblPersons.Name_Personnel, tblPersons.VesselName, tblPersons.SailoutDate, tblPersons.Type, tblPersons.VesselName, Max(IIf([direction]='up',[time_transfer],Null)) AS Time_transfer_UP, Max(IIf([direction]='Down',[time_transfer],Null)) AS Time_tranfer_DOWN
FROM tblPersons, QRY_Numberofsailingdays
GROUP BY tblPersons.Name_Personnel, tblPersons.SailoutDate, tblPersons.Type, tblPersons.VesselName, tblPersons.VesselName
HAVING (((tblPersons.SailoutDate) Between [Forms]![FRM_Working_Time_Personnel]![TXT_startdate] And [Forms]![FRM_Working_Time_Personnel]![TXT_enddate]));