Question

我正在制作一个名为＆＃34; go fish＆＃34;为了一堂课。

player1Hand = [2, 4, 6, 8, "J", "Q", "K"]
player2Hand = [3, 4, 5, 6, 9, 10, "A"]
player1Guesses = [2, 8, "J", 4, "Q"]
player2Guesses = [6, 9, "A", 5, 3]

基本上有5个回合（总共10个输出）。如果玩家1猜测在玩家2手中，那么我应该输出＆＃34; HERE＆＃39; S MY CARD＆＃34;和＆＃34; GO FISH＆＃34;如果卡不在手中，反之亦然。我得到了它的工作，但我一直没有索引错误。

for i in range(20):
    if player1Guesses[i] in player2Hand:
        print ("HERE'S MY CARD")
    else:
        print ("GO FISH")
    if player2Guesses[i] in player1Hand:
        print ("HERE'S MY CARD")
    else:
        print("GO FISH")

我尝试将范围更改为21和19但我仍然得到相同的错误和输出。

GO FISH
HERE'S MY CARD
GO FISH
GO FISH
GO FISH
GO FISH
HERE'S MY CARD
GO FISH
GO FISH
GO FISH
Traceback (most recent call last):
  File "C:\Users\Allen\Dropbox\Computer Science\GoFish.py", line 8, in <module>
    if player1Guesses[i] in player2Hand:
IndexError: list index out of range

我得到了我需要的正确输入但由于某种原因它仍然说索引超出范围。即使程序有效，为什么会出现此错误？我对编码也有点新意，如果你看到任何更简单或更简单的事情，我可以随意使用我的代码！提前谢谢！

- avbirm

Answer 1

你的问题在于：

for i in range(20):
    if player1Guesses[i] in player2Hand:

您迭代了20个项目（0到19），但列表中只有5个：

player1Guesses = [2, 8, "J", 4, "Q"]

更改为range(5)不会抛出错误，您也可以检查i是否小于player1Guesses的长度以及您当前正在进行的检查。同样适用于player2Guesses。

Answer 2

检查i是否为有效索引，i的值必须小于列表的长度。

player1Hand = [2, 4, 6, 8, "J", "Q", "K"]
player2Hand = [3, 4, 5, 6, 9, 10, "A"]
player1Guesses = [2, 8, "J", 4, "Q"]
player2Guesses = [6, 9, "A", 5, 3]

for i in range(20):
    if i < len(player1Guesses) and player1Guesses[i] in player2Hand:
        print ("HERE'S MY CARD")
    else:
        print ("GO FISH")
    if i < len(player2Guesses) and player2Guesses[i] in player1Hand:
        print ("HERE'S MY CARD")
    else:
        print("GO FISH")

Answer 3

迭代列表的实际长度：

length_of_list = len(player1Guesses)
for i in range(length_of_list):
if player1Guesses[i] in player2Hand:
    print ("HERE'S MY CARD")

即使输出正确，列表索引也会超出范围？

3 个答案: