我正在尝试将JSON文件(menu.json)读取到数组(myList),以便运行一个函数(PopulateRecords),该函数将使用HTML行填充我的jQuery菜单插件。理想情况下,我只需稍后更新JSON文件即可动态更改菜单选项。
我的JSON文件是menu.json:
{"pavers":
[
{"display": "Brukstone", "url": "brukstone.html"},
{"display": "Bulovar", "url": "pavers/bulovar.html"},
{"display": "Cobble", "url": "pavers/cobble.html"},
{"display": "Cracovia", "url": "pavers/cracovia.html"},
{"display": "Filtrapave", "url": "pavers/filtrapave.html"},
{"display": "Holland", "url": "pavers/holland.html"},
{"display": "Old Munich", "url": "pavers/oldmunich.html"},
{"display": "Strassen Classic", "url": "pavers/strassen.html"},
{"display": "Strassen Bavaria (Tumbled)", "url": "pavers/strassenbavaria.html"},
{"display": "Strassen Barvaria II (Non-tumbled)", "url": "pavers/strassenbavariaii.html"},
{"display": "Vavel Stone (Tumbled)", "url": "pavers/vavel.html"},
{"display": "Vavel Stone II (Non-tumbled)", "url": "pavers/vavelii.html"}
]}
我的HTML
<!DOCTYPE html>
<html>
<head>
<!-- -->
<!-- Sources -->
<!-- -->
<link type="text/css" rel="stylesheet" href="css/demo.css" />
<link type="text/css" rel="stylesheet" href="../dist/css/jquery.mmenu.all.css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript" src="../dist/js/jquery.mmenu.all.min.js"></script>
<script src="https://cdn.vaadin.com/vaadin-core-elements/latest/webcomponentsjs/webcomponents-lite.min.js"></script>
<link rel="import"
href="https://cdn.vaadin.com/vaadin-core-elements/master/vaadin-combo-box/vaadin-combo-box.html">
<!-- -->
<!-- Attach function.js which contains PopulateRecords-->
<!-- -->
<script type="text/javascript" src="functions.js"></script>
<!--SETUP for jQuery mmenu plugin-->
<script type="text/javascript">
$(function() {
$('nav#menu').mmenu();
});
</script>
</head>
<body>
<nav id="menu">
<ul>
<li><a href="#id01">Pavers</a>
<div id="id01"></div>
</li>
</ul>
</nav>
<script type="text/javascript">
// CALL JSON DATA
var myList;
$.getJSON('menu.json')
.done(function (data) {
myList = data;
});
// POPULATE MENU ITEMS FROM ARRAY
PopulateRecords("01",myList);
</script>
</body>
</html>
调用的PopulateRecords函数位于html头中附加的单独的functions.js文件中。
该功能的javascript是:
function PopulateRecords(id, arr) {
var out = "<ul>";
var i;
for(i = 0; i<arr.length; i++) {
out += '<li><a href="' + arr[i].url + '">' + arr[i].display + '</a></li>';
}
out += "</ul>";
document.getElementById("id"+id).innerHTML = out;
}
它应该如何工作: PopulateRecords函数(在HTML中的<script>
标记中调用)应该传递div元素的id号,该元素是nav中的占位符(id01)菜单HTML。它还传递一个数组,该数组从menu.json文件(在HTML中的<script>
标记中也称为)中填充。然后它会按照jQuery mmenu所需的正确格式(列出项目和href)注入html。
注意:我已成功测试了具有声明的javascript数组的PopulateRecords函数。所以,只要传递一个值为&#39; url&#39;和&#39;显示&#39;。
当然,因为我不熟悉这个概念,这让我相信问题在于我无法解析JSON文件。在关注这个问题之后,我转向堆栈溢出社区寻求帮助。
编辑:正在进行的调试笔记:
1)以下是更新的JSON调用。通过将PopulateRecords调用移动到&#39; .done&#39;结果会停止“myList not defined error&#39;”,但仍然不会填充表格( img1 )。
var myList;
$.getJSON('menu.json')
.done(function (data) {
myList = data;
PopulateRecords("01",myList);
console.log(myList.pavers);
console.log(myList);
console.log(data);
});
2)我还在&#39; .done&#39;中添加了几个console.log调用。用于调试。调用页面时,日志不返回任何内容。
答案 0 :(得分:1)
在调用函数之前,您可能需要等待DOM加载。尝试做
var myList;
$.getJSON('menu.json')
.done(function (data) {
myList = data;
PopulateRecords("01",myList);
console.log(myList.pavers);
console.log(myList);
console.log(data);
});
内
$(document).ready(function(){ ... });
看起来像是:
$(document).ready(function(){
var myList;
$.getJSON('menu.json')
.done(function (data) {
myList = data;
PopulateRecords("01",myList);
$('nav#menu').mmenu();
console.log(myList.pavers);
console.log(myList);
console.log(data);
});
})
仅供我参考:
html:
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
</head>
<body>
<div>
<label id="menuTitle"></label>
<ul id="menu">
</ul>
</div>
<script>
$(document).ready(function(){
$.getJSON('menu.json').done(function(data){
$('#menuTitle').html(data.name);
var lis = ''
for(var i = 0; i < data.options.length; i++)
lis += '<li><a href="'+ data.options[i].url+'">' + data.options[i].name + "</a></li>";
$('#menu').html(lis);
});
});
</script>
</body>
JSON:
{
"name": "aMenu",
"options": [
{
"name": "option 1",
"url": "#"
},
{
"name": "option 2",
"url": "#"
},
{
"name": "option 3",
"url": "#"
},
{
"name": "option 4",
"url": "#"
}
]
}