Question

我试图创建一对不可变的POJO来处理XML的序列化和反序列化，如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<Outer xmlns="http://example.com">
  <Foo>outer foo</Foo>
  <Inners>
    <Inner>
      <Bar>inner 1 bar</Bar>
      <Baz>inner 2 baz</Baz>
    </Inner>
    <Inner>
      <Bar>inner 2 bar</Bar>
      <Baz>inner 2 baz</Baz>
    </Inner>
  </Inners>
</Outer>

我需要能够序列化和反序列化包含Outer列表和Inner列表的Inner。

我可以为此创建一个序列化器没有问题，但我的反序列化器失败，异常com.fasterxml.jackson.databind.JsonMappingException: Duplicate property 'Inners' for [simple type, class BrokenTest$Outer]

以下是传递序列化和失败反序列化的单元测试：

import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.dataformat.xml.XmlMapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlElementWrapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlRootElement;
import org.testng.annotations.Test;

import java.util.Arrays;
import java.util.List;

import static org.testng.Assert.assertEquals;
import static org.testng.Assert.assertNotNull;

public class BrokenTest
{
    private static final String NAMESPACE = "http://example.com";

    @JacksonXmlRootElement(localName="Outer", namespace = NAMESPACE)
    public static class Outer
    {
        @JacksonXmlProperty(localName="Foo", namespace = NAMESPACE)
        public final String foo;

        @JacksonXmlProperty(localName="Inner", namespace = NAMESPACE)
        @JacksonXmlElementWrapper(localName = "Inners", namespace = NAMESPACE)
        public final List<Inner> inners;

        @JsonCreator
        public Outer(
                @JacksonXmlProperty(localName="Foo", namespace = NAMESPACE) final String foo,
                @JacksonXmlProperty(localName="Inners", namespace = NAMESPACE) final List<Inner> inners)
        {
            this.foo = foo;
            this.inners = inners;
        }
    }

    @JacksonXmlRootElement(localName="Inner", namespace = NAMESPACE)
    public static class Inner
    {
        @JacksonXmlProperty(localName="Bar", namespace = NAMESPACE)
        public final String bar;

        @JacksonXmlProperty(localName="Baz", namespace = NAMESPACE)
        public final String baz;

        @JsonCreator
        public Inner(
                @JacksonXmlProperty(localName="Bar", namespace = NAMESPACE) final String bar,
                @JacksonXmlProperty(localName="Baz", namespace = NAMESPACE) final String baz)
        {
            this.bar = bar;
            this.baz = baz;
        }
    }

    @Test
    public void serializeInner() throws Exception
    {
        Inner inner = new Inner("inner bar", "inner baz");
        ObjectMapper mapper = new XmlMapper();
        String serialized = mapper.writeValueAsString(inner);
        assertEquals(serialized, "<Inner xmlns=\"http://example.com\"><Bar>inner bar</Bar><Baz>inner baz</Baz></Inner>");
    }

    @Test
    public void deserializeInner() throws Exception
    {
        String serialized = "<Inner xmlns=\"http://example.com\"><Bar>inner bar</Bar><Baz>inner baz</Baz></Inner>";
        ObjectMapper mapper = new XmlMapper();
        Inner inner = mapper.readValue(serialized, Inner.class);
        assertNotNull(inner);
        assertEquals("inner bar", inner.bar);
        assertEquals("inner baz", inner.baz);
    }

    @Test
    public void serializeOuter() throws Exception
    {
        Outer outer = new Outer("outer foo", Arrays.asList(new Inner("inner 1 bar", "inner 1 baz"), new Inner("inner 2 bar", "inner 2 baz")));
        ObjectMapper mapper = new XmlMapper();
        String serialized = mapper.writeValueAsString(outer);
        assertEquals(serialized, "<Outer xmlns=\"http://example.com\"><Foo>outer foo</Foo><Inners><Inner><Bar>inner 1 bar</Bar><Baz>inner 1 baz</Baz></Inner><Inner><Bar>inner 2 bar</Bar><Baz>inner 2 baz</Baz></Inner></Inners></Outer>");
    }

    @Test
    public void deserializeOuter() throws Exception
    {
        String serialized = "<Outer xmlns=\"http://example.com\"><Foo>outer foo</Foo><Inners><Inner><Bar>inner 1 bar</Bar><Baz>inner 1 baz</Baz></Inner><Inner><Bar>inner 2 bar</Bar><Baz>inner 2 baz</Baz></Inner></Inners></Outer>";
        ObjectMapper mapper = new XmlMapper();
        Outer outer = mapper.readValue(serialized, Outer.class); // fails
        assertNotNull(outer);
        assertEquals("outer foo", outer.foo);
        assertEquals(2, outer.inners.size());
        assertEquals("inner 1 bar", outer.inners.get(0).bar);
        assertEquals("inner 1 baz", outer.inners.get(0).baz);
        assertEquals("inner 2 bar", outer.inners.get(1).bar);
        assertEquals("inner 2 baz", outer.inners.get(1).baz);
    }
}

如果我更改com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "Inners" (class BrokenTest$Outer), not marked as ignorable (2 known properties: "Foo", "Inner"])的构造函数上的@JacksonXmlProperty注释以使用Outer＆＃34;我可以获得不同的异常（localName）内＆＃34;而不是＆＃34; Inners＆＃34;。

有没有办法创建一对适用于这四个测试用例的POJO？

编辑：这是使用杰克逊版本2.7.3

Answer 1

这是杰克逊XML处理中的known bug。

解决方法是更改app.directive('same', function () { return { require: 'ngModel', link: function (scope, element, attr, mCtrl) { mCtrl.$parsers.push(function(value) { var prev = $(element[0]).parent().prev().find('input'); var prev_value = prev.val(); var is_valid = value == prev_value; mCtrl.$setValidity('same', is_valid); element[0].setCustomValidity(!is_valid ? "Must be the same" : ""); }); } }; });构造函数中<form name="register"> <div style="margin-bottom: 10px"> <input placeholder="password" ng-model="newuser.password" type="password" required /> </div> <div style="margin-bottom: 10px"> <input placeholder="password repeat" ng-model="newuser2.password" type="password" required same /> </div> </form>上的注释，以便本地名称不在XML文档中。

以下是有效的单元测试版本：

inners

无法使用Jackson XmlMapper

1 个答案: