Question

在我的文本冒险游戏中，其中一个命令是“take”，这要求用户同时输入字母'T'以及其中的一个项目他们在的房间。
我已经把这个输入分成了命令和项目，但我遇到了if语句的问题。我有第一部分检查命令部分是否等于'T'，但我还要检查此输入是否有一个“项目”部分。我尝试使用.isEmpty()和!= null以及使用.contains()。

这是我的代码：

public Command getCommandFromResponse(String response) throws IllegalArgumentException{
    String[] split = response.split(" ");

    if (split.length < 1){
        throw new IllegalArgumentException("Invalid command.");
    }

    Command command = new Command(split[0]);
    if (split.length >= 2) {
        command.setItem(split[1]);
    }
    return command;
}

这是采取方法：

else if(userCommand.command.equalsIgnoreCase("T") && /*if userCommand contains an item*/){                 
    //Split the input String into two parts, command and item
    userCommand = getCommandFromResponse(userInput.nextLine());
    if (locale.item != null) {
        if (userCommand.item.equalsIgnoreCase(locale.item.itemName)) {
            //add the item to the player's inventory
            player1.inventory.add(locale.item);
            System.out.println("\tA " + locale.item + " was added to your inventory");
            System.out.println("\n\tYou can view your inventory by pressing 'I' or drop an item by pressing 'D'.");
            if (locale.item.itemName.equals("map")) {
                System.out.println("\n\tTo view the map press 'M'.");
            }
            //Add the item's worth to the score and set the items worth to zero to prevent double scoring
            player1.score += locale.item.value;
            System.out.println("\n\t" + locale.item.value + " points have been added to your score.");
            System.out.println("\n\tThis is your current score: "+player1.score);
            //remove the item from the current location
            locale.item = null;
            break;
        } else {
            System.out.println("\n\tThat item is not at this location.");
        }
    } else {
        System.out.println("\n\tThere is no item to pick up here");
    }
}//End of Take

这是我的Command类：

public class Command {

    String command;
    String item;
    public Command(String comm){
        command = comm;
    }

    public Command(String comm, String item){
        this.command = comm;
        this.item = item;
    }

    public void setCommand(String command){
        this.command = command;
    }

    public void setItem(String item){
        this.item = item;
    }

    public String getCommand(){
        return this.command;
    }

    public String getItem(){
        return this.item;
    }

    public String toString(){
        return this.command + ":" + this.item;
    }

}

这些是我的物品：

//Items {itemName, itemDes}
    static Item[] items = {
            new Item ("map","a layout of your house", 10 ),
            new Item ("battery", "a double A battery", 5),
            new Item ("flashlight", "a small silver flashlight", 10),
            new Item ("key", "this unlocks some door in your house", 15),
    };

如果不清楚，我会有更多代码。

Answer 1

我的建议是按照以下方式进行：

变化

if (userCommand.item.equalsIgnoreCase(locale.item.itemName)) {

到

if (userCommand.item!=null && userCommand.item.equalsIgnoreCase(locale.item.itemName)) {

这是最简单的方法，如果命令中没有项目，则不会抛出异常。

（如果这不是你的问题，我很抱歉，但这就是我认为你的意思。）

检查用户输入是否包含项目

1 个答案: