Question

我得到了这个非常简单的mysqli查询失败并返回此消息：

致命错误：未捕获错误：在M：\ xampp \ htdocs \ insert \ form-handler.php中调用boolean上的成员函数bind_param（）：17堆栈跟踪：＃0 {main}抛出M：\ xampp第17行\ htdocs \ insert \ form-handler.php

HTML：

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Document</title>
</head>
<body>
    <form action="form-handler.php" method="POST">
        <input type="text" name="firstname">
        <input type="text" name="lastname">
        <input type="submit">
    </form>
</body>
</html>

PHP：

$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];

$mysqli = new mysqli('localhost', 'root', '', 'firstlast');

if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$stmt = $mysqli->prepare('INSERT INTO users (id, firstname, lastname) VALUES ("", ?, ?');

$stmt->bind_param('ss', $firstname, $lastname);

$stmt->execute();

$stmt->close();

我有什么遗漏的吗？感谢。

Answer 1

public class Bill{
      ...
      public String getKey(){
           return date.toString()+payedTo;
      }
}

HahsMap<String,Bill> oldBills = ...
for (Bill bill : bills){

    if (! oldBills.containsKey(bill.getKey()){
          oldBill.put(bill.getKey(),bill)
    }
}

从$stmt = $mysqli->prepare('INSERT INTO users (id, firstname, lastname) VALUES ("", ?, ?)');中删除了!，但您错过$stmt以关闭)

mySQLi插入错误 - 调用成员函数bind_param

1 个答案: