Question

  void setup() {

  for (int i = 0; i < pinCount; thisPin++) {
    pinMode(ledPins[thisPin], OUTPUT);
  }
}

void loop() {      
      digitalWrite(1,HIGH);
      digitalWrite(7,HIGH);
      digitalWrite(11,HIGH);
      delay(10000);
      digitalWrite(1, LOW);
      digitalWrite(2, HIGH);
      digitalWrite(3, LOW);
      delay(2500);
      digitalWrite(1,LOW);
      digitalWrite(2,LOW);
      digitalWrite(3,HIGH);
      digitalWrite(7,LOW);
      digitalWrite(4,HIGH);
      digitalWrite(5,HIGH);
      delay(5000);
      digitalWrite(4,LOW);
      digitalWrite(9,HIGH);
      digitalWrite(11,LOW);
      delay(10000);
      digitalWrite(5, LOW);
      digitalWrite(6, HIGH);
      delay(2500);
      digitalWrite(6, LOW);
      digitalWrite(7, HIGH);
      digitalWrite(8, HIGH);
      delay(5000);
      digitalWrite(8, LOW);
      digitalWrite(9, LOW);
      digitalWrite(10, HIGH);
      delay(2500);
      digitalWrite(10, LOW);
      digitalWrite(11, HIGH);
      digitalWrite(3, LOW);
  }

我们正在制作一个＆＃34;高级停车灯＆＃34;，所以在代码中我需要添加它，以便在任何时候按下按钮，在循环结束时它将运行代码，我将如何做？

我尝试了几件事，但每次都无法解决问题，对此有什么简单的解决方案？

Answer 1

按下按钮时是否尝试设置标记，然后在循环结束时检查是否已设置标记。

设置标志后，您知道该按钮已被按下，因此您可以执行该代码。这样的事情。

boolean buttonPressed = false;

void setup() {    
  for (int i = 0; i < pinCount; thisPin++) {
    pinMode(ledPins[thisPin], OUTPUT);
  }
}

void loop() {      
      digitalWrite(1,HIGH);
      digitalWrite(7,HIGH);
      digitalWrite(11,HIGH);
      delay(10000);
      digitalWrite(1, LOW);
      digitalWrite(2, HIGH);
      digitalWrite(3, LOW);
      delay(2500);
      digitalWrite(1,LOW);
      digitalWrite(2,LOW);
      digitalWrite(3,HIGH);
      digitalWrite(7,LOW);
      digitalWrite(4,HIGH);
      digitalWrite(5,HIGH);
      delay(5000);
      digitalWrite(4,LOW);
      digitalWrite(9,HIGH);
      digitalWrite(11,LOW);
      delay(10000);
      digitalWrite(5, LOW);
      digitalWrite(6, HIGH);
      delay(2500);
      digitalWrite(6, LOW);
      digitalWrite(7, HIGH);
      digitalWrite(8, HIGH);
      delay(5000);
      digitalWrite(8, LOW);
      digitalWrite(9, LOW);
      digitalWrite(10, HIGH);
      delay(2500);
      digitalWrite(10, LOW);
      digitalWrite(11, HIGH);
      digitalWrite(3, LOW);
      if(buttonPressed)
      {
           //code goes here
      }
  }

您需要添加以上内容的是按下按钮时设置buttonPressed = true

Answer 2

如果我理解正确，无论是否按下按钮，您都希望整个循环运行，然后根据循环期间是否按下按钮来运行（或不运行）特殊代码。

如果是这样，你可以写一个函数my_delay（msec）并在循环内调用它而不是延迟。在my_delay中，如果按下按钮直到请求的时间已经过去，你将有一个循环重复测试：

static int lpressed = 0 ;

void my_repeat(int msec)
{
   long start = millis() ;
   for( ; millis()-start < msec; )
   {
      if (digitalRead(button_pin)==PRESSED)
         lpressed = 1 ;
   }
}

然后在循环结束时，您只需测试（并可能重置）变量lpressed并采取相应的行动：

void loop()
{
   // your unconditional code goes here
   if (lpressed)
   {
      lpressed = 0 ; // reset so we can check again in next cycle
      // your conditional code goes here
   }
}

使按钮保持变量并在循环结束时运行代码

2 个答案: