传递另一个选择选项的参数

时间:2016-03-22 08:54:48

标签: html mysql angularjs servlets ionic-framework

我想在另一个选项中查询{{fetch.university_id}} !!这样我就可以从MySQL数据库获得大学入学名单。但我不能得到适当的方式我想fetch.university_id作为docol()方法的参数

<div class="input-label" ng-init="doUni()">

  University

</div>

<select ng-model="fetchData.university" >

  <option name="{{fetch.university_id}}" ng-repeat="fetch in list" >{{fetch.university_name}}</option>

</select>

<div class="input-label" ng-init="doCol()">

  College

</div>

<select ng-model="fetchData.college" >

<option name="{{fetch.college_id}}" ng-repeat="fetch in collist" >{{fetch.college_name}}</option>

</select>

1 个答案:

答案 0 :(得分:0)

<div class="input-label" ng-init="doUni()">

  University

</div>

<select ng-model="fetchData.university" data-ng-change="controllerFunction (fetchData.university )">

  <option name="{{fetch.university_id}}" ng-repeat="fetch in list" >{{fetch.university_name}}</option>

</select>

In your controller :

scope.controllerFunction = function  (obj) {

Paas this to your server to fetch colleges -->  obj.university_id

Initialise the response data to -->  collist