我正在使用规范模式,并且有一个工作实现(取自WhoCanHelpMe Codeplex项目),用于通过NLinq获取数据,通用存储库以及所有这些优点。
根方法是:
public IList<Case> GetCasesByUsername(string username)
{
CaseByUserNameSpecification spc = new CaseByUserNameSpecification(username);
return this.caseRepository.FindAll(spc).ToList();
}
FindAll()方法执行以下操作:
public IQueryable<T> FindAll(ILinqSpecification<T, T> specification)
{
return specification.SatisfyingElementsFrom(this.Session.Linq<T>());
}
并且,SatisfyingElementsFrom()执行此操作:
public virtual IQueryable<TResult> SatisfyingElementsFrom(IQueryable<T> candidates)
{
if (this.MatchingCriteria != null)
{
return candidates.Where(this.MatchingCriteria).ToList().ConvertAll(this.ResultMap).AsQueryable();
}
return candidates.ToList().ConvertAll(this.ResultMap).AsQueryable();
}
因此,对于通过Case的CaseNb属性查询案例,它非常简单。像下面那样的规范适用于我并获得我想要的案例。
public class CaseByCaseNbSpecification : QuerySpecification<User>
{
private string caseNb;
public CaseByCaseNbSpecification(string caseNb)
{
this.caseNb = caseNb;
}
public string UserName
{
get { return this.caseNb; }
}
public override Expression<Func<Case, bool>> MatchingCriteria
{
get { return u => u.CaseNb.Equals(this.caseNb, StringComparison.CurrentCultureIgnoreCase); }
}
}
但是,在跨越多个实体时,我无法理解如何执行此操作。我想要的是一个规范,允许我通过UserName获取案例。基本上,在数据库中,有三个表,这些表已被带入实体。这是实体:
以下是Case类:
public class Case : Entity
{
private ICollection<CaseUser> caseUsers = new HashSet<CaseUser>();
public virtual Patient Patient { get; set; }
public virtual string CaseNb { get; set; }
...
public virtual IEnumerable<CaseUser> CaseUsers { get { return caseUsers; } }
}
这是CaseUser:
public class CaseUser : Entity
{
public virtual Case Case { get; set; }
public virtual User User { get; set; }
...
}
而且,用户:
public class User : Entity
{
private ICollection<CaseUser> caseUsers = new HashSet<CaseUser>();
public virtual Account Account { get; set; }
public virtual string UserName { get; set; }
...
public virtual IEnumerable<CaseUser> CaseUsers { get { return caseUsers; } }
}
如何编写Expression以通过关联表获取数据?
答案 0 :(得分:0)
我相信你的规范实现应该是这样的:
public class CaseByUsernameSpecification : QuerySpecification<Case>
{
private string userName;
public CaseByUsernameSpecification(string userName)
{
this.userName = userName;
}
public string UserName
{
get { return this.userName; }
}
public override Expression<Func<Case, bool>> MatchingCriteria
{
get { return c => c.CaseUsers.Any(cu => cu.User.Username == this.userName); }
}
}