我的项目有问题。当我浏览http://localhost:8080/user/form
以显示UserForm时,会出现以下错误:
警告:找不到带有URI [/ user / form]的HTTP请求的映射 DispatcherSe rvlet,名称为'userservice'
此处归档UserRestServiceController.java
package edu.java.spring.service.user.controller;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.View;
import edu.java.spring.service.user.dao.UserDao;
import edu.java.spring.service.user.model.User;
@Controller
public class UserRestServiceController {
@Autowired
private UserDao userDao;
@Autowired
private View jsonView;
@RequestMapping(value="/user/form,",method = RequestMethod.GET)
public ModelAndView user(){
// System.out.println("anh yeu em ");
return new ModelAndView("UserForm","User",new User());
}
@RequestMapping(value="/user/json/{username}")
public ModelAndView loadUser(@PathVariable("username")String name){
return new ModelAndView(jsonView,"data",userDao.loadUser(name));
}
}
此处归档userservice-servlet.xml
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd ">
<context:component-scan base-package="edu.java.spring.service.user.controller"></context:component-scan>
<context:component-scan base-package="edu.java.spring.service.user.dao"></context:component-scan>
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="order" value="1" />
<property name="suffix" value=".jsp" />
<property name="prefix" value="/user/" />
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.DerbyDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
<property name="mappingLocations">
<list>
<value>classpath:User.hbm.xml</value>
</list>
</property>
<property name="packagesToScan" value="edu.java.spring.service.user.model" />
</bean>
<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.apache.derby.jdbc.EmbeddedDriver" />
<property name="url"
value="jdbc:derby:D:\PROJECTSPRING\userdb;create=true" />
<property name="username" value="" />
<property name="password" value="" />
</bean>
<bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView">
<property name="contentType" value="text/plain"/>
</bean>
</beans>
答案 0 :(得分:0)
在您的班级添加@RequestMapping(value="/user")
,并在方法级别