Question

public class Task implements Runnable
{
   private final String name;
   private final int priority;
   private final Runnable task;

   public Task(String name, int priority, Runnable task)
   {
      if (null == task) throw new NullPointerException("no task provided");
      this.name = name; this.priority = priority; this.task = task;
   }

   /**
    * run() is made final here to prevent any deriving classes 
    * accidentally ruining the expected behavior
    */
   @Override public final void run()
   {
      final Thread thread = Thread.currentThread();

      // cache the current state to restore settings and be polite
      final String prevName = thread.getName();
      final int prevPriority = thread.getPriority();

      // set our thread's config
      thread.setName(name);
      thread.setPriority(priority);

      try { task.run(); } catch (Throwable ignored) {}

      // restore previous thread config
      thread.setPriority(prevPriority);
      thread.setName(prevName);
   }
}

我正在使用上面的代码在JavaFX中创建一个表，但是每次在输入新数据后关闭应用程序时，ID的序列编号会提前100，所以如果我输入3条记录并且第一个符号出现在我的序列是100 101 102关闭程序并重新打开并再输入3个记录，序列为200 201 202 存储此值的变量是什么，为什么每次登录都会增加100？或者我该如何解决这个问题？数据库是DerbyDB，它嵌入了应用程序在C盘上的文件夹中，ID被设置为主键

Answer 1

@James_Duh

您是如何关闭数据库的？我知道你可能会错过这行代码

DriverManager.getConnection("jdbc:derby:;shutdown=true")

希望这会有所帮助 @Strawberry很好编辑哪里是答案

DerbyDB中的增量ID

1 个答案: