Question

在第一次尝试中捕获异常后，有没有办法再次输入try语句？现在我正在使用＆＃34;而＃34;和＆＃34;如果＆＃34;声明，它使代码混乱。有任何想法吗？会尽量简化它，抱歉没有逻辑......

run = True
tryAgain = True
a=0
while run:
try:
    2/a
except Exception:
    if tryAgain:
        tryAgain = False
        a = 1
    else:
        run = False

Answer 1

您可以尝试在break区块中使用try语句：

while True:
    try:
        # try code
        break # quit the loop if successful
    except:
        # error handling

Answer 2

考虑到您是在continue中执行此操作，那么您可以使用tryAgain = True a=0 while True: try: 2/a break # if it worked then just break out of the loop except Exception: if tryAgain: continue else: # whatever extra logic you nee to do here继续回到while循环的开头：

{{1}}

Answer 3

我喜欢使用for循环，以便尝试和尝试不会永远继续下去。然后循环的else子句是放置＆＃34;我放弃＆＃34;的地方。码。这是一个支持＆＃39; n＆＃39;重试＆gt; 1：

a=0
num_tries = 5
for try_ in range(0,num_tries):
    try:
        2/a
    except Exception:
        print("failed, but we can try %d more time(s)" % (num_tries - try_ - 1))
        if try_ == num_tries-2:
            a = 1
    else:
        print("YESS!!! Success...")
        break
else:
    # if we got here, then never reached 'break' statement
    print("tried and tried, but never succeeded")

打印：

failed, but we can try 4 more time(s)
failed, but we can try 3 more time(s)
failed, but we can try 2 more time(s)
failed, but we can try 1 more time(s)
YESS!!! Success...

Answer 4

我是Python的新手，所以这可能不是最佳实践。通过将所有内容集中到一个函数中，然后在except语句中调用该函数，触发异常后，我返回到try语句。

def attempts():
    while True:
        try:
            some code
            break #breaks the loop when sucessful
        except ValueError:
            attempts() #recalls this function, starting back at the try statement
            break
attempts()

希望这能解决您的问题。

Python：运行＆＃34;尝试＆＃34;在异常捕获并解决之后再次

4 个答案: