Question

有没有办法过滤年份= 2014年的第一笔金额，以及年份= 2015年的第二笔金额？

Select productName, sum(sales), sum(sales) 
From Invoices 
Where productName = ?

这似乎超级简单，但是当我添加Where year(InvDate) = 2014时，我意识到我正在过滤那一年的所有结果，当我需要每行两年时。

执行Where year(InvDate) = 2014 OR year(InvDate) = 2015会给我2行，我只想要1行。

结果集应为

ProductName | sum of 2014 sales for this product | sum of 2015 sales for this product

编辑：如何计算（sales_2015 - sales_2014）/ sales_2014

SELECT  vendorpn, (sum(case when year(InvDate) = 2015 then sales else 0 end)  - sum(case when year(InvDate) = 2014 then sales else 0 end))/
                sum(case when year(InvDate) = 2015 then sales else 0 end) 
        from BG_Invoice a inner join BG_Parts b on a.material = b.material 
        where customer = 10011484 and vendorpn = 'LM321-118V'
        group by vendorpn
        having sum(sales) > 0

给我0.055644。计算器给了我0.05892350932。我的sales列dataType为decimal(18,2)

EDIT2：看起来我需要使用超过2个小数位来进行除法。

(CONVERT(DECIMAL(18,8),sum(case when year(InvDate) = 2015 then sales else 0 end))

Answer 1

您可以使用条件聚合执行此操作：

Select productName,
       sum(case when year(InvDate) = 2014 then sales else 0 end) as sales_2014,
       sum(case when year(InvDate) = 2015 then sales else 0 end) as sales_2015
from Invoices
group by productName;

编辑：

对于评论中的问题：

Select productName,
       (sum(case when year(InvDate) = 2015 then sales else - sales end) /
        sum(case when year(InvDate) = 2014 then sales end) 
       ) as ratio
from Invoices
where year(InvDate) in (2014, 2015)
group by productName;

Answer 2

要回答您的评论，您可以使用WITH使用虚拟表然后查询

这是声明：

WITH CTE as (
Select productName,
       sum(case when year(InvDate) = 2014 then sales else 0 end) as sales_2014,
       sum(case when year(InvDate) = 2015 then sales else 0 end) as sales_2015
from Invoices
group by productName;
)
SELECT productName, ((sales_2014 - sales_2015) / sales_2014) as result
FROM CTE

SQL Server：每列不同的日期过滤器

2 个答案: