Question

我正在尝试建立一个食谱程序，询问人们有关食谱的信息并存储它。菜单位于一个只运行的案例陈述中，他们会为他们尝试访问的内容推送任何数字。但是，无论何时按下任何按钮，它都会跳过该选项中的内容并返回菜单。我试过调试，但似乎它识别输入，然后回到菜单。这是它尝试访问的类和第一种方法（但不是

package potluck;
import java.util.*;

import potluck.*;

public class Controller {
    private Scanner input;
    private Member member;
    private AdminMember admin;

    private final static int USER_LOGIN = 0;
    private final static int CREATE_MEMBER = 1;
    private final static int CREATE_ADMIN = 2;
    private final static int CREATE_RECIPE = 3;
    private final static int COMMENT = 4;
    private final static int DELETE_RECIPE = 5;
    private final static int EXIT = 8;

    public Controller(){
        input = new Scanner(System.in);
        startUp();//no better name to be thought of
    }

    public void startUp() {
        // TODO Auto-generated method stub
        int choice;
        do {
            this.displayMenu();
            choice = input.nextInt();
            input.nextLine();// clears carriage return
            //depending on choice takes to a different menu
            switch (choice) {
//              case USER_LOGIN:
//                  member.enterPassword();
//                  break;
        case CREATE_MEMBER: 
            new Member();
            break;
        case CREATE_ADMIN: 
            Member.addAdmin();
            break;
        case CREATE_RECIPE:
            Recipe.addRecipe();
            break;
        case COMMENT:
            Recipe.addComment();
            break;
        case DELETE_RECIPE:
            Recipe.deleteRecipe();
            break;
        case EXIT:
            System.out.println("Thanks for using our software");
            System.exit(choice);
            break;
        default:
            System.out.println("Error, Invalid selection.");
        }
    } while (choice != 8); //choice 8 exits
}
private void displayMenu() {
    System.out.println("1 Create Member");
    System.out.println("2 Create Admin Member");
    System.out.println("3 Create Recipe");
    System.out.println("4 Leave Comment");
    System.out.println("5 Delete Recipe");
    System.out.println("8 Exit");
    System.out.println("Please enter menu option, to exit enter 8");
    }
}

这是它尝试访问的成员类。包装盒; import java.util.Scanner; 公共级会员{

 private int memberID = 0;
 private String name;
 private String alias;
 private String email;
 private String username;
 private String password;
 private Scanner scanner = new Scanner (System.in);

public void Member(){ //constructor
    memberID =+ 1;
    name = "";
    alias = "";
    email = "";
    username = "";
    password = "";

    setName();
    setAlias();
    setEmail();
    setUsername();
    setPassword();
    System.out.println("Member Created");
   }

  public  void addMember() {
     new Member();
  }

所以就像回顾一样。我现在只想让CREATE_MEMBER选项正常工作。无论出现什么问题，其余的都可能出错。

Answer 1

您没有将Member分配给您的变量：

member = new Member();

另请注意，您所谓的构造函数实际上并不是一个。您需要将void删除为一个：

public Member() { //constructor
    // code
}

Answer 2

您使用Member类就像调用其static方法一样。您必须调用构造函数并创建类的实例。

Member member = new Member();

任何类的构造函数都不需要返回类型，因此请删除void字。

public Member() {
   ...
}

如果要将1作为属于** all * instances的全局变量添加到您的memberID，则必须将该变量定义为static。所以：

private static int memberID = 0;

最后，您的addmember(..)方法无效。如果要在创建的实例Member member = new Member();中初始化实例变量，则必须修改构造函数或创建大量的setter。

public class Member {

   // constructor
   public Member(String name, String alias ...) {
      this.name = name;
      this.alias = alias;

      ...

   }

   // setters
   public void setName(String name) {
      this.name = name;
   }

   public void setAlias(String alias) {
      this.alias = alias;
   }

...

}

尝试制作简单的食谱计划

2 个答案: