Question

节目输出将是这样的：

string1 : stack
string2 : overflow
changed string is : sotvaecrkf

* string1的每个第N个字符由string2的第N个字符连接

但是每次运行时我的DevC ++都会崩溃并向string1和string2提供输入

C代码：

#include<stdio.h>
#include<string.h>
void zips();


void main(){
zips();
}


void zips(){

printf("enter string1:");
char s1[120],s2[120],s[120],y,z;
scanf("\n%s",s1);
printf("\nenter string2:");
scanf("\n%s",s2);
int leng,increasedlength,i;
int leng1=strlen(s1),leng2=strlen(s2);
if(leng1==leng2){
    leng=leng1;
}
else if(leng1<leng2){
    increasedlength=leng2-leng1;
    leng=leng2-increasedlength;
}
else{
    increasedlength=leng1-leng2;
    leng=leng1-increasedlength;
}
for(i=0;i<=leng;i++){
    y=s1[i];
    printf("%s",y);
    z=s2[i];
    printf("%s",z);
    strcat(y,z);
}   
}

Answer 1

也许是这样的。请注意，无法在简单的char类型上进行字符串连接。

#include <stdio.h>
#include <string.h>

int main (void) {
    char s1[] = "stack";                            // skipped the string inputs
    char s2[] = "overflow";
    char str[120];
    size_t i;                                       // var type returned by `strlen`
    size_t index = 0;
    size_t leng1 = strlen(s1);
    size_t leng2 = strlen(s2);
    size_t leng = leng1 <= leng2 ? leng1 : leng2;   // ternary operation to get min length
    if(leng == 0 || leng * 3 > sizeof str)
        return 1;                                   // will not fit output string
    for(i = 0; i < leng; i++) {                     // note `<=` changed to `<`
        str[index++] = s1[i];                       // buiuld the output string
        str[index++] = s2[i];
        str[index++] = ' ';                         // pad string
    }
    str[index - 1] = '\0';                          // terminate string
    printf("%s\n", str);
    return 0;
}

节目输出：

so tv ae cr kf

程序崩溃（字符串操作）

1 个答案: