Question

我目前正在使用JavaScript进行雷区游戏。我在游戏结束时遇到了问题。我有三个难度级别，因此很容易给用户45个猜测，中间40个猜测和高级是35个猜测。但是，出于某些原因，当我将它设置为中间/高级时，它会继续进行45次猜测，而不是应该停止的位置。

在我花了很长时间看着它并改变不同的东西，比如变量的名称和编辑代码。猜测工作正常，所以每个猜测实际上算作1猜测现在他们计算为3.代码现在停在35。

var number_of_guesses = 0;
var maximum_guesses = 45;
var intermediate_guesses = 40;
var advanced_guesses = 35;
var number_of_hits = 0;
var number_of_misses = 0;

var element = opener.document.getElementById("easy");
if (element.checked === true)
{
maximum_guesses = 45;
}

var intermediate = opener.document.getElementById("intermediate");
if (element.checked === true)
{
intermediate_guesses = 40;
}

var advanced = opener.document.getElementById("advanced");
if (element.checked === true)
{
advanced_guesses = 35;
}

number_of_guesses++;
if (number_of_guesses > maximum_guesses)
{
window.alert("Sorry, you have run out of guesses!");
return;
}

number_of_guesses++;
if (number_of_guesses > intermediate_guesses)
{
window.alert("Sorry, you have run out of guesses!");
return;
}

number_of_guesses++;
if (number_of_guesses > intermediate_guesses)
{
window.alert("Sorry, you have run out of guesses!");
return;
}

有人可以告诉我： a）如何使每个猜测计数为1而不是3？ b）如何正确设置每个难度？

Answer 1

尝试让所有三个选项设置maximum_guesses变量，而不是针对不同的困难设置三个不同的变量。然后检查一个变量。

var number_of_guesses = 0;
var maximum_guesses = 45;
var number_of_hits = 0;
var number_of_misses = 0;
// notice the missing intermediate_guesses and advanced_guesses vars

var element = opener.document.getElementById("easy");
if (element.checked)
{
maximum_guesses = 45;
}

var intermediate = opener.document.getElementById("intermediate");
if (intermediate.checked)
{
maximum_guesses = 40; // changed this to maximum_guesses
}

var advanced = opener.document.getElementById("advanced");
if (advanced.checked)
{
maximum_guesses = 35; // changed this to maximum_guesses
}

number_of_guesses++; // you only need this once
if (number_of_guesses > maximum_guesses)
{
window.alert("Sorry, you have run out of guesses!");
return;
}

编辑：您还有一个错字，当您检查是否检查了中间和高级复选框时，您仍在检查easy元素。

编辑2 ：此外，在您的代码中，您正在调用number_of_guesses++;三次，这就是每次猜测计数3次的原因。对于他们只计算一个，你只需要第一个。每次检查时，数字都会保持不变，因此您不需要增加三次。

编辑3 ：在我的代码中，请注意我删除了您选中的if语句中的=== false部分是否已选中复选框。

我的猜测数量不会停在正确的水平

1 个答案: