Question

我想检查php中两个日期之间是否存在sat或sun。

$fromDate = '03/21/2016';
$toDate = '03/28/2016';

我在这里尝试了其他解决方案，但他们并没有很好地运作。我希望它在laravel 5.2中，所以如果有任何简单的方法来处理这个，请指导我。谢谢！

更新如果在两个日期之间有工作日（周一至周五），我也想知道。我需要它，因为用户只能选择sat和Sunday，所以在这种情况下，我可以隐藏他的工作日选项。所以我需要的是一种方法，告诉我开始和结束日期是周末还是工作日或两者都有。

Answer 1

您可以使用date("N")获取当天的当天日期，并添加日期之间的天数差异。如果这大于或等于6，则周末之间或周末之间是周末

//Get current day of week. For example Friday = 5
$day_of_week = date("N", strtotime($fromDate));

$days = $day_of_week + (strtotime($toDate) - strtotime($fromDate)) / (60*60*24)
//strtotime(...) - convert a string date to unixtimestamp in seconds.
//The difference between strtotime($toDate) - strtotime($fromDate) is the number of seconds between this 2 dates. 
//We divide by (60*60*24) to know the number of days between this 2 dates (60 - seconds, 60 - minutes, 24 - hours)
//After that add the number of days between this 2 dates to day of week. So if first date is friday and days between this 2 dates is: 3 the sum will be 5+3 = 8 and it's bigger than 6 so we know it's a weekend between.



if($days >= 6){
  //we have a weekend. Because day of week of first date + how many days between this 2 dates are greater or equal to 6 (6=Saturday)
} else {
  //we don't have a weekend
}

Answer 2

试

<?php
    $is_weekend = 0;
    $fromDate = strtotime('2016-03-21');
    $toDate = strtotime('2016-03-28');
    while (date("Y-m-d", $fromDate) != date("Y-m-d", $toDate)) {
        $day = date("w", $fromDate);
        if ($day == 0 || $day == 6) {
            $is_weekend = 1;
        }
        $fromDate = strtotime(date("Y-m-d", $fromDate) . "+1 day");
    }
    echo $is_weekend;

锄头有帮助：）

如何检查php中两个日期之间是否有周末？

2 个答案: